Why does the precipitate dissolve, reappear, and then dissolve again?

  • Thread starter Thread starter billabonger77
  • Start date Start date
  • Tags Tags
    Dissolve
AI Thread Summary
The discussion revolves around the behavior of a precipitate formed from mixing silver nitrate and hydrochloric acid, which initially creates silver chloride (AgCl). When ammonium hydroxide is added, AgCl dissolves, forming soluble silver hydroxide. Upon reintroducing hydrochloric acid, AgCl precipitates again due to its insolubility. Adding sodium thiosulfate causes the precipitate to dissolve once more, forming a different compound. The discussion highlights the dynamic nature of precipitate formation and dissolution based on chemical reactions and solubility rules.
billabonger77
Messages
2
Reaction score
0
why does the precipitate dissolve, reappear, and then dissolve again??

Homework Statement



i have a chem lab due tuesday and was wondering if anyone may please help me on it!

the problem:
Mix silver nitrate solution and hydrochloric acid solution. Product is a precipitate
2. Add ammonoum hydroxide solution drop by drop. precipitate dissolves.
3. Add hcl again. precipiate forms
4. add sodium thiosulfate..precipitate dissolves.

why does the precipitate dissolve, reappear, and then dissolve again??

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
1. AgNO3 + HCl -> HNO3 + AgCl
HNO3 is soluble, but AgCl isn't (see solubility rules), so it precipitates.

2. AgCl + NH4OH -> AgOH + NH4Cl
It dissolves? Really? :/

3. AgOH + HCl -> AgCl + H2O
AgCl is insoluble again, so it precipitates again.

4. 2AgCl + Na2S2O3 -> Ag2S2O3 + 2NaCl
Uhhh...

Well, at least you have the equations :P.
 
hey how does the equations get affected when i use
1> 5mL of 0.1 M of silver nitrate solution mixed with 5mL of 0.1 M HCl.

2. then added 6 M ammoniumn hydroxide solution, drop by drop

3. then added 10 mL of 0.1 M HCl solution

4. then added 5mL of .15 M sodium thiosulfate
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
Back
Top