Why Does the Second Harmonic Frequency Double in a Fixed Rope?

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The fundamental frequency of a rope fixed at both ends is 30Hz, and the second harmonic frequency is calculated to be 60Hz. In the fundamental mode, the rope has one loop, corresponding to a wavelength of λ/2. For the second harmonic, the rope has two loops, which means the wavelength is halved. This relationship between frequency and wavelength explains why the second harmonic frequency doubles. Understanding these principles is essential for solving similar problems in wave mechanics.
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Homework Statement



If the fundamental frequency for a rope fixed at both ends is 30Hz, what is the frequency of the second harmonic?


Homework Equations



v=f*wavelength



The Attempt at a Solution



correct answer is 60Hz. Can somebody please explain? Thank you.
 
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In the fundamental mode of vibration, the rope contains one loop which is λ/2. In the second harmonic the number of loops are two. Then what is the new wavelength?
 
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