Why Don't Intermolecular Forces Play a Significant Role in CO2 Molecules?

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SUMMARY

The discussion centers on the intermolecular forces present in carbon dioxide (CO2) molecules, specifically addressing the absence of significant dipole-dipole interactions due to the molecule's linear geometry, resulting in no net dipole moment. Participants clarify that CO2 primarily exhibits Van der Waals forces, particularly London dispersion forces, while acknowledging the presence of quadrupole-quadrupole interactions, which are weaker than dispersion forces. The quadrupole moment of CO2 is significantly larger than that of diatomic oxygen (O2), yet the overall intermolecular forces in CO2 are dominated by dispersion forces due to their higher polarisability.

PREREQUISITES
  • Understanding of molecular geometry and dipole moments
  • Knowledge of intermolecular forces, including Van der Waals forces
  • Familiarity with quadrupole moments and their significance
  • Basic principles of molecular polarisability
NEXT STEPS
  • Research the role of London dispersion forces in molecular interactions
  • Study the calculation methods for quadrupole-quadrupole interactions using DFT-SAPT
  • Explore the differences in boiling points related to intermolecular forces in various compounds
  • Investigate the effects of electronegativity on molecular interactions and polarisability
USEFUL FOR

Chemistry students, molecular physicists, and researchers interested in the properties of gases and intermolecular forces, particularly in the context of carbon dioxide and related compounds.

UMath1
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I understand that due to the geometry of the CO2 molecule it ends up have no net dipole moment. But why doesn't the central carbon atom experience intermolecular forces from the oxygen atoms of other CO2 molecules. What I mean is why can't CO2 form an arrangement where the dipole forces still play a role?
I have attached a drawing of what I think this would look like.
Screenshot_2016-02-03-21-48-40.png
.
 
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That's more or less how the molecules are arranged in the solid carbon dioxide.
 
Then why is it said that CO2 molecules only have Van der Waals forces. If the molecules are arranged that way, doesn't it indicate the oresence of dipole dipole forces?
 
Who said that quadrupole quadrupole interactions aren't important in CO2?
 
This is what my textbook, Zumdahl Chemistry, says:
20160205_091627.jpg

It makes no mention of the quadrupole interactions and says the only forces present are London Dispersion.
 
Oversimplification.
 
So there are indeed quadrupole forces which make the intermolecular forces in CO2 stronger than a diatomic molecule like say O2?
 
Yes, although O2 has a weak permanent quadrupole moment, too. For these multipole moments to be absent completely, you need spherical particles like noble gas atoms.
 
How does O2 have a quadrupole moment?
 
  • #10
Why not? There is some negative charge accumulating in the bonding region and corresponding positive charge on the oxygens.

PS: Just looked it up. The quadrupole moment of oxygen is 14 times smaller than the one of CO2.
 
  • #11
How would the magnitude of the forces from quadrupole interactions compare with the dispersion forces? The quote from the book could still be true if the quadrupole interactions are much weaker than dispersion forces.
 
  • #12
My guess is that the author of that book confused "van der Waals interactions" (=*any* weak interaction, including residual forces between static multipoles) with "London dispersion force" (one of the many sources of weak interactions, between dynamic multipoles). CO2 certainly does have static quadrupole-quadrupole interactions. Exact quantitative sizes are very hard to estimate. Could be anything, and would need explicit calculation to compare with the dispersion forces. Such calculations can be done (with DFT-SAPT, for example), but are entirely trivial to set up.
 
  • #13
I don't thini it is so hard to estimate. The quadrupole moments and polarisability of CO2 is known from experiment which allows in principle to calculate the forces, or at very least, to estimate their relative size.
 
  • #14
Actually I wanted to ask just that. It seems as if the London forces are stronger than Quadrupole forces because CSe2 has a much higher boiling point than CO2. Although CO2 would likely experience a stronger quadrupole force because of the higher electronegativity difference.
 
  • #15
So are LDFs stronger than quadrupolemforces?
 
  • #16
UMath1 said:
Actually I wanted to ask just that. It seems as if the London forces are stronger than Quadrupole forces because CSe2 has a much higher boiling point than CO2. Although CO2 would likely experience a stronger quadrupole force because of the higher electronegativity difference.
Yes, but CSe2 has also a much higher polarisability than CO2. Hence, dispersion forces are also stronger than in the case of CO2.
 
  • #17
But it doesn't have a permanent polarity. While the dispersion forces are stronger, the quadrupole forces are weaker. So, dispersion forces play a bigger role than quadrupole forces?
 

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