Why don't my two approaches to finding c(t) match in Laplace transform problem?

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Homework Help Overview

The problem involves finding the time-domain function c(t) from a given transfer function C(s) and an input function r(t) using Laplace transforms. The original poster attempts to solve the problem using two different methods but finds that the results do not match.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster describes two methods for finding c(t), one involving direct substitution into the inverse Laplace transform and the other using the Laplace transform of r(t) before applying the transfer function. Participants question the correctness of the first method and seek clarification on the steps taken.

Discussion Status

Participants are actively discussing the discrepancies between the two approaches. Some guidance has been offered regarding the transformation of products in Laplace space, and there is an acknowledgment of the convolution theorem, which may clarify the misunderstanding. The discussion is ongoing, with no explicit consensus reached yet.

Contextual Notes

There is a mention of potential confusion regarding the application of Laplace transforms and the assumptions made in the original poster's methods. The original poster expresses uncertainty about the validity of their first approach.

ViolentCorpse
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Homework Statement


I'm given a transfer function
C(s)=10R(s)/(s+4)

And I have to find c(t) for r(t)=6u(t)

The Attempt at a Solution


First I did this problem by taking inverse laplace of the transfer function, and inserting the value of r(t) in it.

Next I did the same problem by first taking laplace of r(t), inserting it in the transfer function equation and then taking the inverse laplace to get c(t).

The answers I got from the two approaches don't match. I got c(t)=60e-4t by the first method and c(t)=15(1-e-4t) by the second method.

I don't understand why they don't match. I know that the second approach is giving me the right answer, but I can't figure out what's wrong with the former approach?

Thank you for your time!
 
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Did you perhaps transform the product in transformed space to a product in normal space?
 
ViolentCorpse said:
First I did this problem by taking inverse laplace of the transfer function, and inserting the value of r(t) in it.
What do you mean you inserted the value of r(t) in it? Please show your actual work.
 
C(s)=10R(s)/(s+4)

1st method:
c(t)=10e-4tr(t) (Is this what you meant by transforming a product to normal space, Orodruin?)
Since r(t)=6u(t)
So, c(t)=60e-4tu(t)

2nd method:
r(t)=6u(t)
R(s)=6/s
So
C(s)=60/s(s+4)
Applying partial fractions to get
C(s)=15/s - 15/(s+4)
c(t)=15(1-e-4t)
 
Last edited:
ViolentCorpse said:
c(t)=10e-4tr(t) (Is this what you meant by transforming a product to normal space, Orodruin?)

Yes, the product of two Laplace transforms is not the Laplace transform of the product, it is the Laplace transform of the convolution of the functions. You therefore cannot do what you did in this step.
 
Orodruin said:
Yes, the product of two Laplace transforms is not the Laplace transform of the product, it is the Laplace transform of the convolution of the functions. You therefore cannot do what you did in this step.
I vaguely recalled something like that the moment you mentioned it before. I feel so stupid.

Thanks so much, Orodruin!
 

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