Why don't neutral atoms distort the electric field?

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In a positively charged conductor with a cavity containing a positive charge, the system reaches electrostatic equilibrium, resulting in zero electric field within the conductor as per Gauss's law. Although neutral atoms have internal charges, their effects on the electric field are negligible at distances greater than approximately 10^-10 meters, allowing for the approximation that the electric field is zero. The presence of negative charge on the cavity's interior surface counteracts the positive charge, ensuring that the electric field inside the conductor remains zero. Classical electrostatics simplifies the treatment of charge by considering it as a fluid, while real-life scenarios involve complexities like atomic polarization and magnetic fields. Overall, the averaging effect of numerous atoms at larger distances diminishes the impact of individual atomic charges on the electric field.
davidbenari
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Suppose I have a positively charged conductor with a cavity. There's a positive charge inside the cavity and the system has reached electrostatic equilibrium. Then there's negative charge surrounding the cavity and positive charge on the surface of my conductor. If I apply gauss law to the interior of the conductor I conclude that the electric field is zero at every point of my gaussian surface, and if it weren't so, then charged particles would be accelerating or whatever.

But my question is: why don't the atoms in the interior affect the electric field? I mean, even if the atoms are neutral (consider now a non-conducting material) they have charges inside that should somehow alter the electric field in the neighborhood.

What's going on?

Thanks.
 
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davidbenari said:
Suppose I have a positively charged conductor with a cavity. There's a positive charge inside the cavity and the system has reached electrostatic equilibrium. Then there's negative charge surrounding the cavity and positive charge on the surface of my conductor. If I apply gauss law to the interior of the conductor I conclude that the electric field is zero at every point of my gaussian surface, and if it weren't so, then charged particles would be accelerating or whatever.
... didn't you say there was a positive charge inside the cavity?
If your gaussian surface enclosed the positive charge, then wouldn't the flux through the surface be non-zero?

But my question is: why don't the atoms in the interior affect the electric field? I mean, even if the atoms are neutral (consider now a non-conducting material) they have charges inside that should somehow alter the electric field in the neighborhood.
Quite right - the electric field from "neutral" atoms is not exactly zero everywhere. That is an approximation, which holds very well at distances greater than around 10-10m.

Try this: treat a neutral atom as a shell of negative charge surrounding an equal positive charge ... place a gaussian surface around the entire thing and work out the field.

However
 
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If there is a positive charge inside my cavity, and the system has reached electrostatic equilibrium, then there is also negative charge surrounding the interior surface of the cavity so as to make the electric field inside the conductor zero by gauss's law.
 
http://www.physics.sjsu.edu/becker/physics51/images/23_20ConductingTube.JPG

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I'm starting to think that it's more practical to assume that the only things that exist are swarming protons and electrons for these problems. Is this the idea in classical electrostatics?
 
If there is a positive charge inside my cavity, and the system has reached electrostatic equilibrium, then there is also negative charge surrounding the interior surface of the cavity so as to make the electric field inside the conductor zero by gauss's law.
...
Like (c)
In the diagram you showed me, the brown area is a solid conductor - there is no field inside the conductor.
The white area in the middle is a cavity - there is certainly an electric field inside the cavity.
The diagram is not quite accurate - diagram (c) should have more "+" signs on the outer surface than the others.
But I think I'm clear on what you are talking about now.

Classical electrostatics treats charges as infinitely divisible fluids.
This gets modified slightly when you realize that, for normal solids, the mobile fluid is the negatively charged one - but for most purposes it does not matter.

Electrons and protons belong to the particle model of charge - they are not the only charged particles, so just talk about positive and negative charge unless otherwise specified.

IRL: atoms can become polarized as well as charged, and they carry magnetic as well as electric fields, thisall makes things tricky ... as you advance in your education you will learn how to handle these things in more detail. Meantime you'll notice that the electrostatics you are doing involves quite long distances and very large numbers of atoms so the small effects of individual atoms will tend to average out.
 
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