Why Is MnO2 Deposited at Positive Potentials in Electrochemical Reactions?

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The discussion centers on the electrochemical deposition of MnO2, which occurs at positive potentials despite the negative standard potential of the half-reaction. The reaction Mn2+ + 2 H2O → MnO2 + 4 H+ + 2 e− has a standard potential of -1.22 V, indicating it is non-spontaneous and requires energy input. Participants note that the deposition of MnO2 must happen in anodic conditions, contrasting with the deposition of metallic Cr, which occurs at negative potentials. The inquiry focuses on why MnO2 deposition cannot take place in the negative potential range, emphasizing the need for external electric energy for both reactions. Understanding these potential requirements is crucial for optimizing electrochemical processes involving manganese dioxide.
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Mn2+ + 2 H2O - MnO2 + 4 H+ + 2 e− ( −1.22 V), this reaction is acucurate. the standard potential is negative, then why all the work for the formation of MnO2 need to be done in anodic potential?
 
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According to what you wrote for the reaction (interpreting for one wrong "-" symbol, needs to be an arrow), the half-reaction is an oxidation and requires energy in order to occur. The negative half-reaction potential tells you that the half reaction is not spontaneous and so requires energy to be supplied.
 
my question is in three electrode system: working electrode, Pt counter electrode, and Ag/AgCl reference electrode.
for example, Mn2+ + 2 H2O -MnO2 + 4 H+ + 2 e− ( −1.22 V), the deposition of Mno2 will be accomplished on postive potential. Cr3+ +3e- Cr ( −0.74 V), the depsotion of metallic Cr will be accomplished on negative potential.
I Know for both the half-reactions, they are non-spontaneous and need external electric energy. My point is why the deposition of Mno2 is not done in negative potential range.
 
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