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Why is resistivity inversely proportional to resistance for NTC semiconductors?
I Why is resistivity inversely proportional to resistance for NTC semiconductors?
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Resistivity is inversely proportional to resistance in NTC (Negative Temperature Coefficient) semiconductors due to their temperature-dependent conduction properties. As temperature increases, the charge carriers in NTC materials become more mobile, leading to lower resistivity and, consequently, lower resistance. This relationship is critical for applications in temperature sensing and circuit protection. The discussion highlights the importance of understanding these properties in the context of thermistors and their conduction models. Overall, the inverse relationship plays a significant role in the functionality of NTC semiconductors.
Consider an extremely long and perfectly calibrated scale. A car with a mass of 1000 kg is placed on it, and the scale registers this weight accurately. Now, suppose the car begins to move, reaching very high speeds. Neglecting air resistance and rolling friction, if the car attains, for example, a velocity of 500 km/h, will the scale still indicate a weight corresponding to 1000 kg, or will the measured value decrease as a result of the motion?
In a second scenario, imagine a person with a...
Dear all,
in an encounter of an infamous claim by Gerlich and Tscheuschner that the Greenhouse effect is inconsistent with the 2nd law of thermodynamics I came to a simple thought experiment which I wanted to share with you to check my understanding and brush up my knowledge. The thought experiment I tried to calculate through is as follows.
I have a sphere (1) with radius ##r##, acting like a black body at a temperature of exactly ##T_1 = 500 K##. With Stefan-Boltzmann you can calculate...
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire.
We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges.
By using the Lorenz gauge condition:
$$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$
we find the following retarded solutions to the Maxwell equations
If we assume that...
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