Why is the average moment of a dipole zero?

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The discussion centers on the average dipole moment of an electron in a circular orbit around a nucleus, specifically questioning why the time average of the dipole moment is zero. Despite the dipole moment being constant in magnitude (p = eR), its vector nature means that the direction changes continuously as the electron orbits, leading to cancellation over a complete cycle. The participants confirm that while there is an instantaneous dipole, it does not result in a permanent dipole due to this cancellation effect. The key takeaway is that the vector nature of the dipole moment causes the average to be zero over time. Understanding this concept is crucial for grasping the behavior of dipoles in atomic systems.
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let's say we have an electron circling the nucleus (like the bohr's hydrogen atom), i don't understand why the average wrt to time of the moment of the diople is zero?
we have this equation: \frac{\int_{0}^{T}pdt}{T}
well obviously the diople, p, is constant throughout the elctron's motion, and it ahs the value p=eR where e is the electro's charge and R is the radius of motion, so unless I am missing something the average should be eR, so why am i wrong here?

thanks in advance.
 
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The dipole is a vector.
 
i know that it's defined as a vector which its direction is along the radius, does it mean that on the whole circle the vectors cancel each other, obviously they do.
thanks.
 
loop quantum gravity said:
i know that it's defined as a vector which its direction is along the radius, does it mean that on the whole circle the vectors cancel each other, obviously they do.
thanks.

Yes. The atom has an instantaneous, but not a permanent dipole.
 
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