Why Is the Centripetal Acceleration Positive in Uniform Circular Motion?

AI Thread Summary
In the discussion about centripetal acceleration in uniform circular motion, a child swings a tennis ball on a string, calculating the centripetal acceleration to be -740 m/s². The negative sign arises from the vector nature of acceleration, indicating its direction opposite to the radius vector, but it can be disregarded when using scalar values. The length of the string is correctly identified, but the radius of the circle must consider gravitational effects, which were not explicitly stated in the problem. The centripetal acceleration calculated is approximately 75 times the acceleration due to gravity, suggesting that the impact of gravity on the radius can be negligible in this scenario. Understanding these concepts is crucial for correctly applying physics principles in circular motion problems.
Rijad Hadzic
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Homework Statement


A child swings a tennis ball attached to a .750 m-string in a horizontal circle above his head at a rate of 5.00 rev/s What is the centripetal acceleration of the tennis ball?

Homework Equations


angular speed \omega = 2pi/T
speed = r\omega

a_c = -v^2 /r
a_c = -\omega ^2 r

The Attempt at a Solution


So its 5 rev/s, or .2s in 1 revolution. Using angular speed I get 10pi radians per second
Plugging in,

a_c = -(10pi)^2 (.750 m) = -740 m/s^2

But my books answer is 740 m/s^2.

I don't understand why my answer is negative, even though I used the correct formulas. Does anyone know why?
 
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Rijad Hadzic said:
I don't understand why my answer is negative
The minus sign is in the formula because the acceleration vector is in the opposite direction to the radius vector. But you are working with scalars, not vectors, so you can drop the minus sign and just say in words which way the acceleration is (if you need to specify it, which you probably do not here).
By the way, the answer is not quite right. The given distance is the length of the string, not the radius of the circle. Gravity should be taken into account.
 
haruspex said:
By the way, the answer is not quite right. The given distance is the length of the string, not the radius of the circle. Gravity should be taken into account.

What does gravity have to do with the length of the string??
 
Rijad Hadzic said:
What does gravity have to do with the length of the string??
It does not alter the length of the string, but it does alter the radius of the circle.
 
haruspex said:
It does not alter the length of the string, but it does alter the radius of the circle.

Oh I see. I got you I think I understand why. I'm not sure why but the question didn't state assume no force of gravity, but I think it was suppose to. This is in the 2d motion chapter in my first physics class, so I don't think they consider stuff like that yet.
 
Rijad Hadzic said:
Oh I see. I got you I think I understand why. I'm not sure why but the question didn't state assume no force of gravity, but I think it was suppose to. This is in the 2d motion chapter in my first physics class, so I don't think they consider stuff like that yet.
As you found, the centripetal acceleration is roughly 75g, so in this case the shortening in radius is very small and can be ignored.
 
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