Why Is the First Transistor in a Darlington Pair Connected to the Load Side?

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SUMMARY

The first transistor in a Darlington pair is connected to the load side to ensure adequate base current for the second transistor, enabling it to provide sufficient collector current to activate the load. This configuration requires a minimum Vce of approximately 3 volts for optimal performance, as driving the second transistor directly from the Vcc rail can lead to inadequate saturation and higher voltage drops. The use of the collector rail instead of Vcc introduces negative feedback, enhancing amplification stability. Overall, Darlington pairs are not ideal for switching applications due to their significant Vce voltage drop in the ON state.

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Why is the first transistor in the D-pair connected to one side of the load and not directly to the Vcc rail.
As I understand, the purpose of the first transistor is to supply enough base current, so that the second transistor has adequate collector current to turn on the load.

Fig here:
http://www.sciencelobby.com/junction-transistors/images/darlington-pair.gif
 
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The first transistor needs ~ 3 volts Vce to perform well, so you cannot drive the Darlington second transistor into saturation. Even with the first transistor fully saturated, the second transistor has a Vce of over a volt (min). Darlington is ok if Vce >=4 volts in my opinion. Darlington is not a good switching application because Vce voltage drop is too high in ON state.

Bob S
 
Tapping from the collector rail instead of Vcc provides some negative feedback which makes the amplification more stable.

Also, darlington pairs are self contained units. Adding extra resistance to tap from Vcc instead of a collector is a waste of power, especially when they are used in high current applications.
 

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