Why is the speed of water waves dependent on depth?

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The speed of water waves is influenced by water depth due to the relationship between wave velocity and wavelength. In deep water, the wave speed is determined by the formula c = √(gL/(2π)), indicating that deeper water allows for faster wave propagation. Conversely, in shallow water, the speed is given by c = √(gd), where the wave speed decreases as the depth decreases. This change occurs because water particles in deep water move in circular orbits, while in shallow water, the bottom friction alters these orbits to become elongated, slowing the wave. Thus, the interaction between wave characteristics and water depth is crucial in understanding wave dynamics.
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Why is the speed of water waves dependent on the depth?
 
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The velocity, c, of a simple sinusoidal surface water wave is described by, where L is the wavelength and d the water depth:

c = \sqrt {\frac{{gL\tanh \left( {\frac{{2\pi d}}{L}} \right)}}{{2\pi }}}

Note that when d > L /2

\tanh \left( {\frac{{2\pi d}}{L}} \right) \approx 1

so the velocity for deep water reduces to

c = \sqrt {\frac{{gL}}{{2\pi }}}

and when d << L/2

\tanh \left( {\frac{{2\pi d}}{L}} \right) \approx \left( {\frac{{2\pi d}}{L}} \right)

So the velocity becomes

c = \sqrt {gd}

This is because the water particles are moving in (nearly) circular orbits in deep water. As the water shoals the bottom exerts a drag which elongates the orbit to an ellipse, which gets flatter and flatter with shoaling.
 
Roughly speaking, friction with the bottom slows the wave so that waves in deeper water are faster. The more precise derivation, showing that the wave speed is proportional to the square root of the depth is what studiot gives.
 
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