Why is there a b in the equation for mean?

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The discussion centers on understanding the inclusion of "b" in the equation for calculating the mean when scaling exam marks. The equation 55 = 70a + b is derived from the linear transformation Y = aX + b, where the mean of Y is affected by both the scaling factor 'a' and the constant 'b'. The standard deviation also plays a crucial role, as it is determined by the scaling factor alone, leading to the equation 6.96 = 8.7a. Solving these two equations allows for the determination of the values of 'a' and 'b'. The clarification emphasizes that 'b' adjusts the mean while 'a' affects the spread of the data.
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[Solved]Stats question regarding mean

Homework Statement


Yo.Exam marks,X've mean 70 and standard deviation 8.7.The marks need to be scaled using the formula Y=aX+b so that the scaled marks,Y've mean 55 and standard deviation 6.96.Find the values of a and b.*From the answer sheet -to form equation for mean it's 55=70a+b,why is there "b" in there?


Homework Equations


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The Attempt at a Solution



55=70a+b
U don't need this,I just need some clarity on the above * thing.Pls?
 
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The formula for mean is "linear"- add the values and divide by n- which means that if Y= aX+ b, then mean(Y)= a*mean(X)+ b so your first equation is a(70)+ b= 55.

Formula for standard deviation is "root-mean-square":
\sqrt{\Sigma \frac{(X-\mu)^2}{n}}
so the standard deviation of Y= aX+ b is
\sqrt{\Sigma \frac{((aX+b)-(a\mu+b))^2}{n}}= \sqrt{\Sigma\frac{a^2(x-\mu)^2}{n}}= a\sigma
where \mu and \sigma are the mean and standard deviation of X respectively. Since the stadard deviation of X is 8.7 and you want the standard deviation of Y to be 6.96, you must have 6.96= a(8.7).

It should be easy to solve the equations 70a+ b= 55 and 8.7a= 6.96 for a and b.
 
Thanx so much for ur stuff and kind,clear explanations.Solved.Cya.~The End~
 
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