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Why is there a negative 1?

  1. Oct 28, 2013 #1
    RvqoQwI.png

    When using L'Hospital's rule to differentiate this function, why does the second term have a negative 1 multiplying it? Is it not already negative? Is it because of the -h in the expression?
     
  2. jcsd
  3. Oct 28, 2013 #2

    Mark44

    Staff: Mentor

    Since the limit is on h, that's the variable used in differentiation. So, yes, the -1 comes about from differentiating f(x - h) with respect to h.
     
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