Why is there force on a dielectric inserted into a capacitor

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When a dielectric slab is partially inserted into a capacitor connected to a constant voltage source, a force pulls the dielectric further in due to the electric field's interaction with the induced polarization. This occurs because the insertion of the dielectric increases the capacitance, leading to an increase in charge on the plates while maintaining constant voltage. The potential energy of the capacitor does increase, but the work done by the electric field on the dielectric is greater than the work done against the external force, resulting in a net force that pulls the dielectric in. In contrast, when the capacitor is disconnected from the voltage source, the charge remains constant, and inserting the dielectric would require external work to overcome the potential energy increase. Thus, the behavior of the dielectric in these two scenarios illustrates the distinct effects of constant voltage versus constant charge conditions.
BearShark
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Hey, we have learned in class that if you partialy insert a dielectric slab into a capacitor where voltage is held constant, there is a force pulling the dielectric farther into the capacitor. This gets me consfued. I know the more dielectric material there is in the capacitor, the capacitence would increase. Since this capacitor is connected to a voltage source, and voltage is held constant, then the charge on the plates would have to increase. However, this would mean the potential energy inside of the capacitor would increase. Wouldn't that mean I would have to apply force to push the dielectric in? How come there's a force pushing it in?
 
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There is two different cases:
1. Push dielectric material on a capacitor C with initial charge Q, disconnected to voltage source.
2. Push dielectric material on a capacitor C connected to a constant V voltage source.
Please, think about these cases.
 
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