Why is there gravity at a distance?

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The discussion centers on the implications of Einstein's field equations (EFE) regarding gravity at a distance, specifically how mass curves space even in a vacuum. The local stress-energy influences local curvature, yet the vacuum surrounding a mass still exhibits curvature due to the Riemann curvature tensor, despite the Ricci curvature tensor being zero. The analogy to electromagnetic fields illustrates that fields can exist away from their sources, emphasizing the importance of boundary conditions in understanding gravitational effects.

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Khashishi
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I'm trying to understand the Einstein field equations. My rough understanding is that the local curvature is due to the local stress-energy. Ok, a mass curves space...I get it. But, isn't space curved in the vacuum surrounding a mass? I mean, light is bent by a star even at some distance away from the star. Isn't the stress-energy zero outside the star?

Does this have something to do with the Weyl curvature which isn't included in the field equations?
 
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Remember that there are a few different curvature tensors. The Ricci curvature tensor will be 0 in the vacuum surrounding a mass (per the EFE), but the Riemann curvature tensor may in general be non-zero.
 
I think there's a very nice analogy to E&M here. Even far away from the sources of the fields (the charges and currents), the fields themselves can exist. For example, in a static situation outside a charge distribution:

[tex]\nabla \cdot \vec{E} = 0[/tex]

[tex]\nabla \times \vec{E} = 0[/tex]

But it doesn't mean there is no electric field there. One has to consider boundary conditions. Similarly, Einstein's equations are second order differential equations, so even without a local source, boundary conditions can induce curvature.
 

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