Why is there maximally 1/2 n(n+1) killing vectors?

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SUMMARY

The maximum number of linearly independent Killing vectors in an n-dimensional Riemannian manifold is established as n/2(n+1). This conclusion is derived from analyzing the second derivative of Killing vectors, where the first derivative is constrained to be antisymmetric. Specifically, for n space dimensions, the possible values of the Killing vector ξ are n, while the antisymmetrized first derivative yields n(n-1)/2. Thus, the total number of Killing vectors is calculated as n(n+1)/2.

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It is often stated that there are maximum number of n/2 (n+1) linearly independent killing vectors in an n-dimensional Riemannian manifold.

How is this fact derived?
 
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I'd posted on that in the thread "Riemannian curvature of maximally symmetric spaces".

One first finds an equation for the second derivative of Killing vector ξ. This means that ξ anywhere is a function of ξ and its first derivative at some point. The defining equation for ξ constrains the first derivative of ξ to be antisymmetric or sort-of antisymmetric where ξ itself is 0. For n space dimensions:
  • Possible values of ξ: n
  • Possible values of the antisymmetrized first derivative of ξ: n(n-1)/2
Total: n(n+1)/2
 

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