Why is there no voltage drop through this resistor?

AI Thread Summary
The discussion centers on the lack of voltage drop across a resistor in a circuit involving a 9V battery, a capacitor, and an LED. The voltage readings show 6.5V across the capacitor and 1.5V across the LED, but 0V across the resistor. The explanation points to the behavior of capacitors, indicating that the capacitor is likely holding charge and not allowing current to flow through the resistor. Participants emphasize the importance of understanding capacitor function to grasp the circuit's behavior. The thread concludes with a reminder for politeness in future discussions.
trickybilly
Messages
16
Reaction score
4
I have wired in series: + of 9V battery --- + of 1000 uF capacitor --- 660 Ohm resistor --- + of a green LED --- - of the 9V battery. Remark: the 9V battery is a bit depleted 7.8 V unconnected.

Voltage drop across the capactor is 6.5V, across the LED is 1.5V but 0V across the resistor. Why there is no voltage drop across the resistor?
 
Engineering news on Phys.org
Try this:
1) discharge the capacitor by placing the resistor across it for several seconds.
2) connect everything back up except the LED to - of the battery
3) connect the - of the battery while carefully watching the LED.

What did you see?

4) now remove the capacitor

What do you see now?

BoB
 
trickybilly said:
I have wired in series: + of 9V battery --- + of 1000 uF capacitor --- 660 Ohm resistor --- + of a green LED --- - of the 9V battery. Remark: the 9V battery is a bit depleted 7.8 V unconnected.

Voltage drop across the capactor is 6.5V, across the LED is 1.5V but 0V across the resistor. Why there is no voltage drop across the resistor?
Do you understand how capacitors work?

EDIT: Let me rephrase that: you clearly don't yet understand how capacitors work, so that's where you should focus. Study capacitors for a bit and you will understand what is happening in your circuit. That's where rbelli1 is leading you.
 
@phinds I have received my answer. Do YOU understand it?

2r7y9so.jpg
 

Attachments

  • 2r7y9so.jpg
    2r7y9so.jpg
    35.1 KB · Views: 767
  • Like
Likes Tom.G
trickybilly said:
Do YOU understand it?
You'll bite a helping hand ? Thanks for the warning.
 
  • Like
Likes sophiecentaur and phinds
Since the OP has been answered we will close this thread. Everyone, please remember to be polite in future threads.
 
  • Like
Likes sophiecentaur and jim hardy
Hi all I have some confusion about piezoelectrical sensors combination. If i have three acoustic piezoelectrical sensors (with same receive sensitivity in dB ref V/1uPa) placed at specific distance, these sensors receive acoustic signal from a sound source placed at far field distance (Plane Wave) and from broadside. I receive output of these sensors through individual preamplifiers, add them through hardware like summer circuit adder or in software after digitization and in this way got an...
I have recently moved into a new (rather ancient) house and had a few trips of my Residual Current breaker. I dug out my old Socket tester which tell me the three pins are correct. But then the Red warning light tells me my socket(s) fail the loop test. I never had this before but my last house had an overhead supply with no Earth from the company. The tester said "get this checked" and the man said the (high but not ridiculous) earth resistance was acceptable. I stuck a new copper earth...
I am not an electrical engineering student, but a lowly apprentice electrician. I learn both on the job and also take classes for my apprenticeship. I recently wired my first transformer and I understand that the neutral and ground are bonded together in the transformer or in the service. What I don't understand is, if the neutral is a current carrying conductor, which is then bonded to the ground conductor, why does current only flow back to its source and not on the ground path...
Back
Top