Why is W(VI) more stable than Cr(VI)

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The discussion centers on the differences in reduction behavior between Chromium(VI) and Tungsten(VI), despite their similar atomic radii. The reasoning suggests that the d-orbitals of Chromium (3d) are more strongly bound due to their ability to avoid orthogonality with inner shells, unlike the 4d and 5d orbitals of Tungsten. This leads to the conclusion that the 3d orbitals in Tungsten may be at a higher energy level, influenced by core repulsion effects, particularly involving 5d orbitals. The conversation also touches on the concept of Pauli repulsion between 3d and 4d orbitals, indicating a complex interplay of orbital interactions. Participants express a desire for additional resources to deepen their understanding of these phenomena.
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I'm not sure why Chromium(VI) is reducing and Tungsten(VI) isn't. I also noticed their radius is quite similar. Is that related?
 
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I think it is due to the d-orbitals in Cr being the first ones (3d) they don't have to be orthogonal to inner shells and are therefore relatively more strongly bound than 4d or 5d orbitals in the higher periods. Similar trends can be observed in the other groups, too, e.g. V vs. Nb or Ta, Fe vs Ru or Os.
 
So the (3d) orbitals in Tungsten are potentially higher? Is it due to (s) orbitals core repulsion?
 
Of course not the 3d orbitals in tungsten, but the 5d orbitals.
If you want to view this as the result of a repulsion, it is rather 3d and 4d Pauli repulsion.
 
Ok, could you place here some links... because it's better if I read something for first. The only phenomenon I'm aware of is (ns) orbital energy fall due to Pauli repulsion, and obviously this isn't the entirely same thing.
 

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