Why is water at rest in a rotating cylinder?

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Discussion Overview

The discussion revolves around the behavior of water in a rotating cylinder, specifically addressing why the water appears at rest in a rotating frame and the relationship between centrifugal force and gravitational force. Participants explore the implications of these forces in a rotating reference frame and consider similar scenarios involving rotation at an angle to the vertical.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Homework-related

Main Points Raised

  • Some participants assert that in the rotating frame, the water is at rest, with centrifugal force acting horizontally and gravitational force acting vertically, thus being perpendicular.
  • One participant notes that the axis of rotation must be vertical, leading to the conclusion that the centrifugal force is horizontal and at right angles to gravity.
  • Another participant expresses initial confusion about the concept of being "at rest in the rotating frame" but later indicates improved understanding after discussion.
  • A participant proposes a related problem involving a bucket of water rotated by a rope, questioning how to find the equation of the surface in this scenario.
  • It is suggested that the same principles apply to the bucket problem, as long as the water maintains its shape and the forces acting on it are considered.

Areas of Agreement / Disagreement

Participants generally agree on the basic principles of forces in a rotating frame, but there is ongoing exploration of related scenarios, particularly the bucket problem, which remains less defined and invites further discussion.

Contextual Notes

Participants discuss the conditions under which the water reaches equilibrium and the assumptions regarding the forces acting on the water in both the cylinder and bucket scenarios. The implications of the angle of rotation in the bucket problem are also noted as a point of consideration.

Pi-Bond
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A question I was doing asked to find the equation describing the surface of water placed in a cylinder rotating about its central axis. The question asserts that in the rotating frame, the water is at rest, and centrifugal force and the gravitational force of a volume element are perpendicular to each other. I don't see why this is the case - can anyone explain?
 
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Hi Pi-Bond! :smile:
Pi-Bond said:
The question asserts that in the rotating frame, the water is at rest, and centrifugal force and the gravitational force of a volume element are perpendicular to each other. I don't see why this is the case - can anyone explain?

Which part don't you get? :confused:

In the rotating frame, obviously the water is at rest.

And obviously the gravity is vertical, and the centrifugal force is horizontal.
 
The geometrical axis of the cylinder, which is also the axis of rotation, must be vertical so the centrifugal force must be horizontal: this is clearly at right angles to gravity.

The water must have reached equilibrium so it is rotating with the cylinder (friction forces and viscosity will eventually achieve this). "Rotating with" means that the water is at rest wrt a rotating frame of reference about the axis of rotation of the cylinder.
 
Tiny-tim, what I was confused about is the thing MrAnchovy explained. I think I was getting confused by "at rest in the rotating frame" somehow. But now since both of you have written it out, it makes more sense. Thanks!

As a follow on, I was wondering if something similar to this method can be used to find the equation of the surface if the cylinder is rotated around a point at some angle to the vertical. For example, rotating a bucket of water by using a rope. The question previously mentioned used

dh/dr = Centrifugal Force/Gravitational Force
h: height of water w.r.t centre
r: distance from centre
 
You should work out the bucket/rope problem. It might be helpful for your understanding of this type of problem. But first ask yourself what the angle to the vertical will be for the rope.
 
Hi Pi-Bond! :smile:

(just got up :zzz:)
Pi-Bond said:
… I was wondering if something similar to this method can be used to find the equation of the surface if the cylinder is rotated around a point at some angle to the vertical. For example, rotating a bucket of water by using a rope. The question previously mentioned used

dh/dr = Centrifugal Force/Gravitational Force
h: height of water w.r.t centre
r: distance from centre

Yes, so long as the water keeps the same shape inside the bucket, you can use a rotating frame whose axis is the vertical line through the top of the rope.

Since the surface has a shape such that an object placed on top of the surface will not move relative to the water, it will be in equilibrium in the rotating frame.

Since the only three forces on it are gravity centrifugal and normal, you can take tangential components and get dh/dr = Centrifugal Force/Gravitational Force :wink:
 
After thinking it through, I think I understand it now. Thanks for the help!
 

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