Why my solutions are wrong for this circuit problem?

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SUMMARY

The discussion focuses on solving a circuit problem involving current I2 and voltage Vab. The user initially assumed I1=3A for the left loop (L1) and applied Kirchhoff's Voltage Law (KVL) incorrectly, leading to confusion regarding the relationship between I1, I2, and the current through resistor R1. The correct approach involves recognizing that I1 is already known and establishing a relationship between I1 and I2 without introducing unnecessary variables. The conclusion emphasizes that if I2 equals I1, the current through R1 becomes zero, indicating a need for reevaluation.

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PainterGuy
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Hi, :smile:

I'm sorry for the poor handwriting in the attached scan. I need to find I2 and Vab. I'm more than sure that my solutions are wrong. :redface: But don't know where I went wrong. I started with L1 on the left. I assumed the current in the L1 as I1=3A as supplied by the current supply. Then applied KVL where I assumed overall voltage to be 0V. While applying KVL on L1 the current through R1=3 ohm is I1-I2. Will someone please tell me what goes wrong there? Many thanks for your help.

http://img84.imageshack.us/img84/3064/i2andvab.jpg
 
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I started with L1 on the left. I assumed the current in the L1 as I1=3A as supplied by the current supply. Then applied KVL where I assumed overall voltage to be 0V. While applying KVL on L1 the current through R1=3 ohm is I1-I2

When doing KVL around L1 on the left keep in mind that you're trying to find the current, but you already have it. Its just I1=3A! All you need to do is get an equation that ties the L1 current and the L2 current together, and that's the current through the R1 resistor I(R1) = I1 - I2.

If you really want to do KVL you have to include an unknown voltage for the current source, which is undesirable as it introduces another variable.

Also if I2 = 3A and I1 = 3A then I(R1) = 0 as there's no current going through the 3R resistance, which doesn't sound reasonable.

Do you have a known answer you are working towards?
 
Zryn, many, many thanks for all this help. You are so nice. Sorry, I'm little late with my thanks. :)

Cheers
 

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