Why Na & K are Not Acceptable for Reducing PbCl2

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Sodium (Na) and potassium (K) are not acceptable for reducing PbCl2 due to their inability to form stable chloride compounds like FeCl2 and MgCl2, as NaCl2 and KCl2 are not valid formulas. Although Na and K are higher in the activity series and can theoretically displace Pb2+, practical considerations such as cost and safety make Fe and Mg preferable choices. The reaction would require two moles of Na to produce NaCl, complicating the equation. Ultimately, the choice of reducing agents hinges on both chemical validity and practical application. Understanding these factors is essential for successful reactions involving lead chloride.
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Homework Statement


A question asked to write an equation for the reduction of PbCl2

The answer key was
PbCl2+X ----> Pb+XCl2
where X can be: ...Fe, Mg...but not Na or K

Why are Na or K not acceptable?
 
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Cost could be one reason. And which would you rather work with: sodium / potassium vs. iron / magnesium?
 
Based on the activity series, all of those metals should be able to displace Pb2+ in a single displacement reaction. Maybe it just has to do with the fact that FeCl2 and MgCl2 are valid formula but NaCl2 and KCl2 are not (rather the equation would be PbCl2 + 2Na --> Pb + 2NaCl).
 
Ygggdrasil said:
Based on the activity series, all of those metals should be able to displace Pb2+ in a single displacement reaction. Maybe it just has to do with the fact that FeCl2 and MgCl2 are valid formula but NaCl2 and KCl2 are not (rather the equation would be PbCl2 + 2Na --> Pb + 2NaCl).

The question doesn't make any such type of recommendation though
 
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