Why use the notation (s, a, b, c) for quaternions instead of (s, v)?

Septimra
Messages
27
Reaction score
0
These are the notations of quaternions that i have seen:

q = s + v
q = (s, v)
q = s + ai + bj + ck

where s, a, b, & c are members of the reals

but why not use the notation of:

q = (s, a, b, c)

isn't it the same as the 2nd notation except it is clearer? So why does it take a quaternion to be defined as a 2-tuple over C2 before that notation is possible?
 
Physics news on Phys.org
Hey Septimra.

There are quite a few ways of defining a quaternion and one of them is actually the vector/scalar notation since the multiplication uses the cross product and scalar products to do this.

Aside from that you have your representation you posted above and you can use four variables with multiplication tables.

Basically as long as everything is mathematically consistent then it's all the same anyway.

I'd actually recommend looking at the vector/scalar representation if you want to understand what multiplication of quaternions does geometrically since you can visualize the cross product quite easily (in three dimensions).
 
I asked online questions about Proposition 2.1.1: The answer I got is the following: I have some questions about the answer I got. When the person answering says: ##1.## Is the map ##\mathfrak{q}\mapsto \mathfrak{q} A _\mathfrak{p}## from ##A\setminus \mathfrak{p}\to A_\mathfrak{p}##? But I don't understand what the author meant for the rest of the sentence in mathematical notation: ##2.## In the next statement where the author says: How is ##A\to...
The following are taken from the two sources, 1) from this online page and the book An Introduction to Module Theory by: Ibrahim Assem, Flavio U. Coelho. In the Abelian Categories chapter in the module theory text on page 157, right after presenting IV.2.21 Definition, the authors states "Image and coimage may or may not exist, but if they do, then they are unique up to isomorphism (because so are kernels and cokernels). Also in the reference url page above, the authors present two...
When decomposing a representation ##\rho## of a finite group ##G## into irreducible representations, we can find the number of times the representation contains a particular irrep ##\rho_0## through the character inner product $$ \langle \chi, \chi_0\rangle = \frac{1}{|G|} \sum_{g\in G} \chi(g) \chi_0(g)^*$$ where ##\chi## and ##\chi_0## are the characters of ##\rho## and ##\rho_0##, respectively. Since all group elements in the same conjugacy class have the same characters, this may be...
Back
Top