- #1
pellman
- 684
- 5
Could someone please explain briefly the advantange of doing GR in terms of the tetrad field instead of the metric?
A little background for the beginners who may be reading. As originally formulated by Einstein the dynamical quantify of GR is the spacetime metric [tex]g_{\mu\nu}(x)[/tex]. One can introduce quantities called a tetrad field [tex]e^{I}_{\mu}(x)[/tex] such that
[tex]e^{I}_{\mu}e^{J}_{\nu}\eta_{IJ}=g_{\mu\nu}[/tex]
everywhere, where [tex]\eta_{IJ}[/tex] is the flat Minkowski metric. Then you rewrite all the GR equations in terms of [tex]e^{I}_{\mu}(x)[/tex].
But we have introduced extra degrees of freedom. Any two tetrad fields related by a (local?) Lorentz transformation are equivalent. Why would we want to do that?
A little background for the beginners who may be reading. As originally formulated by Einstein the dynamical quantify of GR is the spacetime metric [tex]g_{\mu\nu}(x)[/tex]. One can introduce quantities called a tetrad field [tex]e^{I}_{\mu}(x)[/tex] such that
[tex]e^{I}_{\mu}e^{J}_{\nu}\eta_{IJ}=g_{\mu\nu}[/tex]
everywhere, where [tex]\eta_{IJ}[/tex] is the flat Minkowski metric. Then you rewrite all the GR equations in terms of [tex]e^{I}_{\mu}(x)[/tex].
But we have introduced extra degrees of freedom. Any two tetrad fields related by a (local?) Lorentz transformation are equivalent. Why would we want to do that?