Why weight change when I put effervescence tablet ?

[Gh778]

That leaves one of the other three.

could you explain ? It's not possible it's Archimedes effect too.

That doesn't look like you are losing mass then.

not mass, weight

A friend of a friend who works in a Lab for analysis has tested with 2 balances of 0.001 g (Kern PEJ and PBJ, I don't know if it's good but it's pro balances), with a small glass/metal in a big glass/metal like I described before. He has near the same result. The weight decrease 0.0273 g (mean) in 2 minutes. He done 4 measures. At least, I can say it's not my balances, I think it's better to have another measures with different balance. I don't tell to him my results so he don't knew that I'm waiting 0.03 g. He don't use exactly the same effervescent tablet but I think it must be CO2 in it too. If someone has a balance precise enough he can do the tests, because I prefer to have a lot of measures and say that don't come from a problem with balance. If you do the test, don't forget to put all thing in container, like that Archimedes law don't interact more after than before.

Image: red is small glass/steel container, black is big glass/steel container, I use support for don't shock the glass. Tablet is block like that it is in water only when I return all the system. I think like that it's not possible to incriminate Archimedes and diffusion.

I added sensor (mountain watch) for measure the pressure in big container and it's never change with big values (only +1.3% max of pressure). Like that I'm sure it's not diffusion of gas.

What do you think I need to add for understand where the problem come from ? I measure weight while 2 minutes, not only for limited escape of gas.

 

[Buckleymanor]

Hi,

I measure weight of : column of water + water + effervescence tablet + cover (hermetic)

When I put effervescence tablet (give a lot of small bubbles) in water and close very quickly the cover, the weight decrease of 0.2g with a precision of 0.01g for the weight-balance. The weight decrease more and more until -0.2g. When I open the cover I can ear pshiiitttt, this could say no gas has move out. I tried with big column (1 liter) and others smaller. Could you explain where is my error when I do experimentation ?

The weight decreases because of bouyancy. The production off a lot of small bubbles causes a decrease in density this results in an increase in bouyancy.The mass remains the same but the atmosphere does not support the extra gas supply from the effervesence tablet in the same way.
Because the experiment is closed the effect of the tablet is like attaching a helium balloon inside the column resulting in a weight decrease.

 

[Simon Bridge]

OK - things that can lead to a lowered weight reading on a balance:

1. there is less mass sitting on the balance
2. there is an additional force acting on the system being weighed
3. it is an artifact of the weighing process
4. the acceleration of gravity has changed

If you rule out #1, then it must be one of the other three.

One thing that springs to mind is when the object being weighed has some sideways vibration, the weight reading can be lowered. I see this in experiments from people who think they have discovered antigravity using rotating widgets. The wobble from the machine throws the weight off - especially for electronic balances - making it look like the machine's weight is reduced.

I usually overcome the effect by making the machine do some work - like lifting a smaller weight over a pulley (compared with machine switched off). Accounting for any very small vibrations caused by the chemical reaction and bubbles would be difficult... but it would work in well with your observations.

You could mount a mirror on the scale surface and bounce a laser off it to put the spot on a wall some meters away to see if there is much vibration present compared with the initial setup?

 

[Simon Bridge]

The weight decreases because of bouyancy. The production off a lot of small bubbles causes a decrease in density this results in an increase in bouyancy.The mass remains the same but the atmosphere does not support the extra gas supply from the effervesence tablet in the same way.
Because the experiment is closed the effect of the tablet is like attaching a helium balloon inside the column resulting in a weight decrease.

Which would also work - except I'd like to see the math.
The system is closed - so one would naively expect that this means the same mass is occupying the same volume before and after release even though CO2 locked into a solid is less dense than released as a gas.
Can you link to an example?

 

[Gh778]

You could mount a mirror on the scale surface and bounce a laser off it to put the spot on a wall some meters away to see if there is much vibration present compared with the initial setup?

I don't have a laser, but could you explain more ?

For vibration, ok when I walk I can see the weight changed, but this cancel if I don't move. At one time there is no bubble moving up in the water (or I can't see it). One "system" has waited the night and I don't watch movement in the water but the weight never change (-0.03g / tab).

If the acceleration of gravity has changed, 2 solids and 2 liquids I use like "references" (I test my balance with "references" before) must changed its weight, but not.

What is an artifact ?

 

[Simon Bridge]

An "artifact" is the name for an erroneous or false reading caused by the way the equipment works or is used ...
http://oxforddictionaries.com/definition/english/artefact
http://en.wikipedia.org/wiki/Artifact_(error )

Have you tried vigorously shaking the container before weighing for the second time?

Does the weight loss stop when new bubbles stop being made?

 

[Gh778]

Have you tried vigorously shaking the container before weighing for the second time?

yes

Does the weight loss stop when new bubbles stop being made?

Yes, but it's not so simple, because new bubbles coming after 2 min but very low number if I compare when the tablet is always there. I stop measuring after 2 min now but like yesterday I have my new system for measuring, I wait this night, and I can say this morning the weight don't change.

If it's an artifact, I would understand how does it works.

 

[Simon Bridge]

I have my new system for measuring, I wait this night, and I can say this morning the weight don't change.

... you need to be clear: do you mean that if you leave the container overnight, there is no weight lost?

 

[Gh778]

no, sorry for me bad english...yesterday I done a measure, the weight decrease -0.03g, I let all the night and the weight don't change in the night, it is always -0.03g in the morning.

 

[Simon Bridge]

No worries - I've had a go trying attract some people who may be able to help you with your quest.
Meantime - did you discover anything that recovered the lost weight? Freezing or something?

 

[Gh778]

did you discover anything that recovered the lost weight? Freezing or something?

I don't have time for this because I focused on Archimedes and diffusion problems. But tomorrow, I will test with new "water->ice->water" cycle and test weight each time. The problem of condensation will be always there. Even if I tested a "simple" bottle of water to see if I weight the good weight.

I appreciate if someone can test and measure weight for have an external point of view with physician knowledge, maybe I forget something in my test.

 

[dlgoff]

IMO gas is escaping. But I'm jumping in here, as safety could be an issue for other experimenters that may read this thread.

https://www.youtube.com/watch?v=nZHGK37jBp8

Need I say more?




Be Safe

 

[Gh778]

Need I say more?

yes, have you read message #36 and see the image ? Because I put tablet in small glass/steal container, and put it in another bigger glass/steel container, I measure the pressure in big container and maybe one or two percent is added. So this don't change the -0.03g I lost

 

[Simon Bridge]

Well you didn't fill the container completely full either.
Outgassing requires that gas escape both walls. But that may happen if the seals are not as good as you think.

Will you show us a video of your setup in progress?

 

[Gh778]

Will you show us a video of your setup in progress?

sure, tomorrow or wednesday

Well you didn't fill the container completely full either.
Outgassing requires that gas escape both walls. But that may happen if the seals are not as good as you think.

It's possible to have diffusion through wall of the first container, but like pressure in the second container is always the same than external pressure, the diffusion through the big container must be near 0.

Have you datas of the diffusion of CO2 through glass and metal function of time and thickness ? Because when I saw the value on internet I don't read big value and something that can gave 0.03g in 2 minutes with 1 g of CO2. And like I said before even there is diffusion, this is the same value with different containers ?

 

[Buckleymanor]

Which would also work - except I'd like to see the math.
The system is closed - so one would naively expect that this means the same mass is occupying the same volume before and after release even though CO2 locked into a solid is less dense than released as a gas.
Can you link to an example?

http://en.wikipedia.org/wiki/Cartesian_diver
Ok.The diver is submerged in water, though the container is submerged in the atmosphere in a similar way.So unless gas is escapeing as digoff hints the production of bubbles within the container is causing a density change through pressure, allowing more bouyancy to the container within the atmosphere.

 

[Gh778]

@Buckleymanor: If I lost weight when there are bubbles, this can say I can move down a mass m1 I recover m1gh, and at bottom I change weight m2 and move up very quickly (acceleration=1000 m/s²) and recover energy from movement, I lost m2gh, I return to first position and I win energy (m1-m2)*gh, like g and h can be very high (in theory), I can win energy even I lost energy due from the dissolution of the tablet, it's not possible.

 

[Buckleymanor]

@Buckleymanor: If I lost weight when there are bubbles, this can say I can move down a mass m1 I recover m1gh, and at bottom I change weight m2 and move up very quickly (acceleration=1000 m/s²) and recover energy from movement, I lost m2gh, I return to first position and I win energy (m1-m2)*gh, like g and h can be very high (in theory), I can win energy even I lost energy due from the dissolution of the tablet, it's not possible.

Your mass does not change.It is your density that is variable due to the introduction of the tablet.
Look at the diver it's mass remains the same but the air within it changes density due to the pressure applied on the bottle.You are applying pressure on the walls of the container as the tablet produces bubbles the whole thing grows slightly as the pressure increases makeing the contents of the container slightly less dense.Which in turn makes it more bouyant within the atmosphere and weighing less.
Unless it is the gas escapeing from the container, then it is looseing mass to the atmosphere and this will also make it weigh less.

 

[Gh778]

@Buckleymanor: ok, now I understood what you want to explain. True, the system is about the same. Bubbles decrease density, this increase volume and so Archimedes force. The weight decrease. You're right.

But now what's happens with energy ? I can move down the system without bubbles and move up with bubbles at any speed. It's not possible to recover more energy than give.

 

[Simon Bridge]

http://en.wikipedia.org/wiki/Cartesian_diver
Ok. The diver is submerged in water, though the container is submerged in the atmosphere in a similar way. So unless gas is escapeing as digoff hints the production of bubbles within the container is causing a density change through pressure, allowing more bouyancy to the container within the atmosphere.

Where in that link is it demonstrated that the overall weight-reading on a scale decreases?
(Or changes at all?) That's what you need to demonstrate.
All I see in the linnk is that the density of the air inside the stopper changes, changing the buoyancy force on the stopper - not the entire bottle.

In Gh778's setup - the air inside the container increases density because additional gas is being added - even though the bubbles decrease the mean density of the liquid, and there is reduced density from the disintegration of the tablet. The overall volume of the setup does no change and neither does the mass (it has been asserted).Consider: If a bottle of compressed helium is in an evacuated chamber, and the whole is sitting, in air at STP, on a sensitive balance. The bottle is opened (by an automated mechanism, remote control, something) allowing the helium to escape and fill the room. All else remaining equal: what do you think would happen to the reading on the balance?

You can even imagine the mass of the chamber+bottle is lighter than the air it displaces so that, filled with helium, it would normally float in the air... and we tether it to the balance.

 

[Gh778]

Maybe it's easier to understand with a basic problem (image):

1/ the system at start
2/ I add bubble object in water, this don't change the mass of water+gas, but the volume of water increase, the external pressure increase, the volume of bubble decrease...

For the delay of transmission of pressure, if water is at altitude 1 meter in the column, the speed of sound is around 340 m/s. The time for reach up is 0, but for reach the bottom time need 0.003 s.
If pressure increase of 100000 Pa in 2 minutes, the differential pressure is around 2.5 Pa / s. It's enough for create a difference of weight I think, no ?

 

[Buckleymanor]

@Buckleymanor: ok, now I understood what you want to explain. True, the system is about the same. Bubbles decrease density, this increase volume and so Archimedes force. The weight decrease. You're right.

But now what's happens with energy ? I can move down the system without bubbles and move up with bubbles at any speed. It's not possible to recover more energy than give.

When you add bubbles you are also adding the energy the introduction of the tablet and the chemical reaction are supplying energy so you are not getting something for nothing.

 

[Gh778]

reaction are supplying energy so you are not getting something for nothing

I thought about that but the energy of chemical reaction is fixed Ec. But you can accelerate an object like you want, with 1000 m/s² for example, you can find an energy greater than Ec with parameter of acceleration, or even the system can have a high constant velocity 10000 m/s for example before to put in contact of water/tablet.

Another tests:
In one case, if I wait a long time: 3 tests on 4, I can say the weight is always at -0.03g
In other case, if I freeze water to ice: 4 tests on 6, I can say the weight come back to original value. So it's not enough to tell something.

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For the delay of transmission of pressure, if water is at altitude 1 meter in the column, the speed of sound is around 340 m/s. The time for reach up is 0, but for reach the bottom time need 0.003 s. If pressure increase of 100000 Pa in 2 minutes, the differential pressure is around 2.5 Pa / m. It's enough for create a difference of weight I think, no ? And the pressure in water depend of speed of sound in water around 1500 m/s, very different of sound in air, how pressure can do for equilibrate in the same time ?

 

[Simon Bridge]

Maybe it's easier to understand with a basic problem (image):

1/ the system at start
2/ I add bubble object in water, this don't change the mass of water+gas, but the volume of water increase, the external pressure increase, the volume of bubble decrease...

How do you add the bubble?

I'm sorry, this example is more complicated than your original one.

 

[Gh778]

How do you add the bubble?

it's just a theoretical problem for understand how pressure works. But if it's more complicated, let it down.

Do you know how delay change a dynamic pressure ? Delay come from speed of sound in the material ?

 

[Simon Bridge]

1. How the bubble go there is important - just magicing it in place means you have added mass to the system (the air in the bubble), displaced some water - which compresses the air already there.
You could push the bubble down from the surface somehow ... the bubble displaces water equal to the volume of the bubble (but the bubble probably compresses too).
You could have a bottle of pressurized gas... you get the idea? It adds complications where you want to remove them.

What I'd suggest is doing away with the tablet and the water, adding a valve and a bottle of compressed CO2.
pressurize the inner container from the bottle ... see if you get weight loss.

You could repeat by carbonating some water, also from the gas bottle.

Remember to include the gas bottle in the weighing.

2. Pretty much - pressure changes cannot travel instantly.
But they will be pretty fast for the small size of your system.

 

[Gh778]

2. Pretty much - pressure changes cannot travel instantly.
But they will be pretty fast for the small size of your system.

Watch new image please (theoretical system)

With height of gas = H = 0.1 m
Surface at contact = S = 0.0036 m²
Speed of sound = V = 340 m/s (decrease when $CO_{2}$ is added but increase with pressure)
Gravity = g = 9.81 m/s²
Difference of pressure = P = 100000 Pa
Duration of bubbles = T = 120 s

Modification of force due to the speed of pressure = $\frac{PHS}{TVg}$

AN = 0.09 g

Pressure at top of water come from :

- each new bubble increase pressure
- bubble increase in size => water move up (very short time)

 

[Buckleymanor]

Where in that link is it demonstrated that the overall weight-reading on a scale decreases?
(Or changes at all?) That's what you need to demonstrate.
All I see in the linnk is that the density of the air inside the stopper changes, changing the buoyancy force on the stopper - not the entire bottle.

In Gh778's setup - the air inside the container increases density because additional gas is being added - even though the bubbles decrease the mean density of the liquid, and there is reduced density from the disintegration of the tablet. The overall volume of the setup does no change and neither does the mass (it has been asserted).


Consider: If a bottle of compressed helium is in an evacuated chamber, and the whole is sitting, in air at STP, on a sensitive balance. The bottle is opened (by an automated mechanism, remote control, something) allowing the helium to escape and fill the room. All else remaining equal: what do you think would happen to the reading on the balance?

You can even imagine the mass of the chamber+bottle is lighter than the air it displaces so that, filled with helium, it would normally float in the air... and we tether it to the balance.

Maybe it is not as obviouse as imagined.
The water inside the bottle represents the air surrounding the container in Gh778's experiment.
The stopper in the link represents Gh778's container.The change in density of the air inside the stopper represents the change in density inside the container.If its sealed properly the container will expand slightly just like the bottle in the video did before it exploded.
It's not a complete sealed system to the atmosphere.
It will either expand, leak, or if too much gas is produced explode.
The change in the buoyancy force of the stopper as the air expands inside it is the same effect the container will have within the atmosphere when the tablet is inserted, bubbles and expansion happen and it becomes more buoyant.

If you were to place a scale below the stopper inside the bottle when you compressed the bottle and as a consiquence the air inside the stopper would also compress, the diver "stopper" would sink.
This would register on the scale if you did the opposite the diver would rise and there would be no reading on the scale.

 

[Gh778]

I measured the additional pressure inside the container (like last drawing show), it's only 38000 Pa with one tablet and a volume big enough for have 0.1 m in height and 36 cm², so the result is 0.034 g. Maybe the lost of weight come from this. This could explain the difference of weight is always the same with different volumes, because If HS (volume) increase, P (pressure) decrease in the same proportion (if temperature is the same).

With height of gas = H = 0.1 m
Surface at contact = S = 0.0036 m²
Speed of sound = V = 340 m/s
Gravity = g = 9.81 m/s²
Difference of pressure = P = 38000 Pa
Duration of bubbles = T = 120 s

 

[Gh778]

I think there is an error in my study with delay due to the pressure. Pressure is not coming at 833 Pa in each second, like steps, it's not an air cylinder very fast. So:

1/ How could I calculate the good differential pressure with a tablet ?
2/ I can replace tablet by air cylinder very fast, this change the Archimedes law ?
3/ With a system at constant speed V=10 m/s, 100 m/s or more in theory, if Archimedes law is changed this would say I can move up less weight on 10 meters for examples and move down the "real" weight. But this would say energy recover can be higher than needed. All energy give by the air cylinder can be recover from pressure of temperature, or energy of accelerating gas goes to momentum of movement ?
4/ Is it possible to reduce weight on a closed system, even gravity is present ?
5/ Why it's not possible to use this system for elevating a rocket ? It's possible to replace gas by water, the only problem is the elevation of temperature.
6/ If there is an up acceleration, the air at bottom add pressure at bottom and cancel a part of move up. But:
6.1/ an object can be on levitation with this ?
6.2/ if the object is heavy compare to mass of air, the up acceleration is only a small part of acceleration of gas ?

 

[Simon Bridge]

Maybe it is not as obviouse as imagined.
The water inside the bottle represents the air surrounding the container in Gh778's experiment.
The stopper in the link represents Gh778's container. The change in density of the air inside the stopper represents the change in density inside the container.

In the archemedes diver, the air stopper (dropper?) changes density because surrounding water from the bottle is pushed into (or out of) it through the hole in the bottom.

Are you supposing that, following your analogy, air from outside the container is forced into (or out of) the container? You realize that the container is supposed to be airtight right?

Finally, the overall density of the dropper + contents, in the diver, changes.
In Gh778's experiment, the overall density of the container + contents does not change.

 

[Simon Bridge]

I think there is an error in my study with delay due to the pressure. Pressure is not coming at 833 Pa in each second, like steps, it's not an air cylinder very fast.

I don't know what you are trying to say. Sorry.
I'm going to try to answer your questions though:

1/ How could I calculate the good differential pressure with a tablet ?

No you can't - you have to measure it.

2/ I can replace tablet by air cylinder very fast, this change the Archimedes law ?

Archemedes law is a law of nature - it is the same for all systems.
Using an a cylinder of compressed gas (I suggest using CO2) and a valve you can pressurze the container quite quickly - it that what you mean?

3/ With a system at constant speed V=10 m/s, 100 m/s or more in theory, if Archimedes law is changed this would say I can move up less weight on 10 meters for examples and move down the "real" weight. But this would say energy recover can be higher than needed. All energy give by the air cylinder can be recover from pressure of temperature, or energy of accelerating gas goes to momentum of movement ?

The laws of physics are the same at a constant speed. Total energy will be conserved as always ... as is momentum. Not all the energy expended will be recoverable though, since some of the processes in your experiment are irreversible.

4/ Is it possible to reduce weight on a closed system, even gravity is present ?

One can reduce the mass in a closed system by turning into energy by E=mc² ... this happens, for instance, in nuclear decay. Apart from that, no, mass is conserved in a closed system ... it is what "closed system" means.
Mass changing normally means that your system is not closed.

5/ Why it's not possible to use this system for elevating a rocket ?

No reason - it is possible to use this system as a rocket. Making high-energy gas at high pressure via a chemical reaction is how most rockets work. BUT - you have to put a hole in the container to get a rocket action.

6/ If there is an up acceleration, the air at bottom add pressure at bottom and cancel a part of move up. But:
6.1/ an object can be on levitation with this ?
6.2/ if the object is heavy compare to mass of air, the up acceleration is only a small part of acceleration of gas ?

The weight-loss of your containers is not evidence of some sort of anti-gravity or levitation method, no.

 

[Gh778]

No you can't - you have to measure it.

I measured the pressure at start and after 2 minutes, the difference is 38000 Pa, but how get the differential pressure and take account of speed of sound ?

One can reduce the mass in a closed system by turning into energy by E=mc2 ... this happens, for instance, in nuclear decay. Apart from that, no, mass is conserved in a closed system ... it is what "closed system" means.
Mass changing normally means that your system is not closed.

not mass but weight, mass is always the same, but weight can decrease with only gravity like external force, nothing else ?

No reason - it is possible to use this system as a rocket. Making high-energy gas at high pressure via a chemical reaction is how most rockets work. BUT - you have to put a hole in the container to get a rocket action.

A part of the system is on the floor. I would like to say, all the system, not a part.

 

[Simon Bridge]

I measured the pressure at start and after 2 minutes, the difference is 38000 Pa, but how get the differential pressure and take account of speed of sound ?

Is http://physics.stackexchange.com/questions/80878/how-speeds-pressure-modify-the-archimedes-law ?

You mean you want to find how the pressure varies within the container?
For that you use several pressure gauges located at different places.
But if you want the equilibrium speed of sound in your gas mixture, you can estimate it.
http://en.wikipedia.org/wiki/Ideal_gas#Speed_of_sound
... you should take Buckleymanor's ideas about buoyancy with some caution.

not mass but weight, mass is always the same, but weight can decrease with only gravity like external force, nothing else ?

Stroctly speaking, weight is the force of gravity on an object. Therefore only a change in the local gravitational field or the change in mass of the object will change the weight.

However, the weight read by a balance is not like that. A balance shows you the net force needed to support the object. If gravity is the only force to balance out, then the scale will read the weight. In your case, this is probably not the case.

I gave you a list of four possible ways the weight-reading could change earlier.

A part of the system is on the floor. I would like to say, all the system, not a part.

Um... OK: it's on the floor... now what?

 

[Gh778]

A friend has let me a balance with a precision of 0.001g and now all is fine the weight is the same. Even this change a little during bubbles move up, it's not more the accuracy.

But now, in a standard bottle, I would like to understand why weight is not greater when bubbles move up, due to the speed of sound in the container. If there is a differential of pressure, the top surface receive pressure with a delay why this don't change the weight ?