Buckleymanor said:
If there was no hole but greater pressure applied to the bottle the same effect would happen.
Only if the dropper could change shape.
Note: When you play with one of these, the change in the volume of the dropper is easily seen.
...the container is not made from an inelastic substance so if you introduce a tablet that has a chemical reaction and bubbles are produced because it is airtight? what happens to the container.
The container expands... this has already been covered, several times, earlier in the thread.
Please reread page 1.
tldr: Gh778 reports no visible change in the overall volume of the container.
So - have you calculated how big the change in size needs to be in order to produce the 30-60mg change in the weight reading?
I did one earlier but it was contested and I haven't revisited it since.
Initial weight reading is: ##W=mg-\rho Vg \qquad \text{...(1)}##
Final weight reading is: ##W-\Delta W = mg-\rho (V+\Delta V)g\qquad \text{...(2)}##
##\quad##...where ##\small \rho\approx 1.204## g/l is the density of the air at room temperature and sea level.
Subtract (2) from (1): $$\Delta W = mg-\rho Vg -\big(mg-\rho (V+\Delta V)g\big)\\
= \rho \Delta V g\\
\Rightarrow (\Delta x)^3 = \frac{\Delta W}{\rho g}
$$
... would give the linear dimension change for isomorphic expansion.
Let's see how big this is:
##\Delta W = (0.01g)\text{ grams}\\
\rho= 1.204\text{ g/l} = 0.001204\text{ g/cm}^3##
$$\Delta x = \left(\frac{0.01}{0.0001204}\right)^{1/3} = 4.4\text{ cm}$$
... that's for a 10mg weight-loss ... 30mg is 6.3cm and 60mg is 7.9cm ... the kinds of figures reported.
... I think he'd
notice don't you?