- #1
pivoxa15
- 2,255
- 1
In my textbook, it had
2Cu2+(aq) + 4I-(aq) -> CuI(s) + I2(aq)
How does that work? First of all it's not balanced. It should be 2CuI(s). But how does CuI(s) form. It should be CuI+.
The book did say excess 4I- was usd to remove Ag+ since it was talking about back titrations. But the reaction as stated dosen't involve Ag. Has the book made mistakes?
2Cu2+(aq) + 4I-(aq) -> CuI(s) + I2(aq)
How does that work? First of all it's not balanced. It should be 2CuI(s). But how does CuI(s) form. It should be CuI+.
The book did say excess 4I- was usd to remove Ag+ since it was talking about back titrations. But the reaction as stated dosen't involve Ag. Has the book made mistakes?