1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Wierd reaction?

  1. Jan 23, 2007 #1
    In my textbook, it had

    2Cu2+(aq) + 4I-(aq) -> CuI(s) + I2(aq)

    How does that work? First of all it's not balanced. It should be 2CuI(s). But how does CuI(s) form. It should be CuI+.

    The book did say excess 4I- was usd to remove Ag+ since it was talking about back titrations. But the reaction as stated dosen't involve Ag. Has the book made mistakes?
  2. jcsd
  3. Jan 24, 2007 #2


    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    No, it's correct (except for the missing 2).

    Cu(+2) is reduced to Cu(+1) and I(-1) is oxidized to I(0).
  4. Jan 24, 2007 #3
    I see. Thanks
  5. Jan 26, 2007 #4


    User Avatar

    Staff: Mentor

    Note: this reaction is interesting as its equilibrium is moved to the right thanks to the very low solubility of CuI.
  6. Jan 27, 2007 #5
    And the solubility is so low that CuI precipitates out as a solid.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Wierd reaction?
  1. Irreversible reactions (Replies: 8)

  2. Redox Reaction (Replies: 4)

  3. Possible Reaction (Replies: 1)

  4. Oxidation reaction (Replies: 9)

  5. Rate of reaction (Replies: 7)