Will someone check my work to see if Im on the right track?

In summary, the conversation is about a collisions and momentum problem involving a 50g bullet fired at a 1.00 kg ballistic pendulum. The question asks for the distance the block rises after being struck by the bullet. The answer involves calculating the impulse and change in momentum, and using the equation v²=u²+2as to solve for the distance. The conversation also mentions that the collision is not elastic, but this does not affect the solution. The final answer is determined to be 5.1m and there are no other missing elements in the solution.
  • #1
camel-man
76
0
This is collisions and momentum problem. for some reason it just seems like a short problem and I am use to doing long problems so I am here to check my work.

the questions is

A 50g bullet is fired vertically up at a 1.00 kg ballistic pendulum . The bullet strikes the block at
1000 m/s and emerges from it at 800 m/s. How far does the block rise? Assume that the
duration of the collision is instantaneous, in other words, during the collision no external forces
were acting on the system

my answer

Impulse given to block=0.050x1000-0.500x800=10=change in the block's momentum=1.00xv→v=10m/s. Using v²=u²+2as with v=0, u=10, a=-g=-9.8, we get 0=100-2x9.8s→s=5.1m.
[The collision isn't elastic but this doesn't matter since we aren't using energy conservation to solve the problem].

Am i missing something else?
 
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  • #2
hi camel-man! :wink:
camel-man said:
Impulse given to block=0.050x1000-0.500x800=10=change in the block's momentum=1.00xv→v=10m/s. Using v²=u²+2as with v=0, u=10, a=-g=-9.8, we get 0=100-2x9.8s→s=5.1m.
[The collision isn't elastic but this doesn't matter since we aren't using energy conservation to solve the problem].

Am i missing something else?

looks ok to me :smile:

(though that's not how a ballistic pendulum works :confused:)
 

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