Will the Box Slide When Equations are Satisfied?

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    Friction Motion
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Understanding impending motion involves two key equations: F = μsN and F ≤ μsN. When the first equation is satisfied, the box will begin to slide, indicating that static friction has been overcome. If the second equation holds, the box remains stationary, as the applied force does not exceed static friction. Once the box starts moving, dynamic friction (μd) comes into play, which is typically less than static friction (μs). This distinction is crucial for analyzing motion and forces in physics problems.
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Homework Statement



I'm trying to understand the whole impending motion stuff.

Homework Equations



Eq.1: F = μsN
Eq.2: F ≤ μsN

The Attempt at a Solution



After obtaining my normal forces and friction force from analyzing my FBD, I should set up the data using these two equations?

And so...if Eq.1 is satisfied then the object, let's say a box, will start to move? And if Eq.2 is satisfied the box will not move?
 
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aaronfue said:

Homework Statement



I'm trying to understand the whole impending motion stuff.

Homework Equations



Eq.1: F = μsN
Eq.2: F ≤ μsN

The Attempt at a Solution



After obtaining my normal forces and friction force from analyzing my FBD, I should set up the data using these two equations?

And so...if Eq.1 is satisfied then the object, let's say a box, will start to move? And if Eq.2 is satisfied the box will not move?

In a wod - correct.

Once eq. 1 is met, the box slides and there is a new coeff. of friction involed, μd or 'dynamic' friction. This coefficient is the ratio of the force F needed to keep the box moving without acceleration to the weight N of the box. μd is generally < μs as I recall (been a long, long time ...).
 

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