Will there be a reaction at the hinge B in this question?

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Discussion Overview

The discussion revolves around the question of whether there is a reaction force at hinge B in a specific mechanics problem involving rods and their weight distribution. Participants explore the implications of ignoring the reaction at hinge B and its effect on the correctness of their answers.

Discussion Character

  • Debate/contested
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant claims to have solved the problem by disregarding the reaction at hinge B, questioning why this approach yields a correct answer.
  • Another participant asserts that half of the weight of rod AB is supported by hinge B, suggesting this contributes to the answer of ##13\over2##.
  • A participant challenges the assertion about the weight distribution, asking how it can be determined that half of AB's weight is on B.
  • Multiple participants note the presence of six scalar unknowns related to reaction forces and three equations of statics, indicating a complex system of equations.
  • One participant expresses uncertainty about whether the lack of a reaction at B is a coincidence or based on solid reasoning.
  • A later reply suggests that the discussion may be more appropriate for a homework forum, implying a need for a more structured approach to the problem.

Areas of Agreement / Disagreement

Participants express differing views on the role of the reaction at hinge B, with some asserting its significance while others question its necessity. The discussion remains unresolved regarding the logic behind ignoring the reaction at B.

Contextual Notes

There are multiple unknowns and equations involved, and the discussion does not clarify the assumptions or definitions that underpin the claims about weight distribution and reaction forces.

Asad Raza
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I have solved this question by completely disregarding the reaction at the hinge B. And surprisingly, answer turns out to be correct. Why is that so?
 

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Half the weight of AB is on B (AB doesn't rotate or move) and that gives you the ##13\over2##.

For the second part I'm too lazy to work it out (you did that already); if you post your work, I (or someone else) may comment (e.g: "it doesn't matter" or "it's a numerical coincidence") :smile:
 
How do we know that half of AB's weight is on B?
 
You have 6 scalar unknowns: two components of each reaction force at the points A,B,C. You also have three equations of statics for each rod. I wish you good luck
 
zwierz said:
You have 6 scalar unknowns: two components of each reaction force at the points A,B,C. You also have three equations of statics for each rod. I wish you good luck
But Reaction at B isn't playing a role. Just explain it to me that whether is that a coincidence or there's some solid logic behind?
 
How can I explain if you already know what plays role here and what does not? :)
 
This should be posted in a homework forum, with an attempt at a solution.

Thread closed.
 

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