Will there be a reaction at the hinge B in this question?

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Asad Raza
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I have solved this question by completely disregarding the reaction at the hinge B. And surprisingly, answer turns out to be correct. Why is that so?
 

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Half the weight of AB is on B (AB doesn't rotate or move) and that gives you the ##13\over2##.

For the second part I'm too lazy to work it out (you did that already); if you post your work, I (or someone else) may comment (e.g: "it doesn't matter" or "it's a numerical coincidence") :smile:
 
How do we know that half of AB's weight is on B?
 
You have 6 scalar unknowns: two components of each reaction force at the points A,B,C. You also have three equations of statics for each rod. I wish you good luck
 
zwierz said:
You have 6 scalar unknowns: two components of each reaction force at the points A,B,C. You also have three equations of statics for each rod. I wish you good luck
But Reaction at B isn't playing a role. Just explain it to me that whether is that a coincidence or there's some solid logic behind?
 
How can I explain if you already know what plays role here and what does not? :)
 
This should be posted in a homework forum, with an attempt at a solution.

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