Work & Capacitance: Calculating Energy Fluctuations

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SUMMARY

The discussion focuses on calculating energy fluctuations in a system with a 100 F capacitor on a DC link that experiences voltage fluctuations up to 300 VDC. The formula used for energy calculation is 1/2 CV², where C represents capacitance and V represents voltage. Participants clarify that the energy at any instant is indeed calculated using this formula, and positive values indicate energy consumption while negative values suggest energy is being returned to the DC link.

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AmazingTrans
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Hi there,

I have a system that trace every 10ms the voltage of the dc link and in parallel there are capacitors on the DC Link that is about 100 F. The DC Link Voltage can raise as high as 300VDC and it fluctuates.
(I am just throwing out numbers as I'm just trying to grasp the concepts)

To find the energy of the system I used 1/2 CV2
From the table here that I calculated. Would it be right to say :
Energy At that Instant would be 1/2 CV2
Energy Consumed would be the positive value, and the negative values would mean there is excessive energy is returned back to the dc link?

PKyFe.jpg


Hope someone could clarify this. Thanks!
 
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Hi AmazingTrans. I see you are new here. http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

That is the energy stored in the capacitance, from sample to sample.
 
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Thanks NascentOxy!
 

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