Work done by gravity on a car rolling down a hill

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The discussion centers on calculating work done by gravity on a car rolling down a hill, with a focus on the formula E = F x cos(θ). A participant mentions obtaining 243 kJ but questions the values used for force (F), distance (x), and angle (θ). The conversation suggests that using the work-energy principle, W = ΔE_P, is more appropriate for this scenario than the traditional formula. Additionally, there is a query about the specific distance represented by 50 cos(8°) m in the context of the problem. The thread emphasizes the importance of correctly applying the relevant formulas to accurately determine the work done by gravity.
physicsmaster123
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I tried E =Fxcos0 but only ended up with 243kJ
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What values of ##F##, ##x##, and ##\theta## did you use and why?
 
Hint: What is the textbook definition of ##\theta## in the formula you stated?
 
Last edited:
physicsmaster123 said:
I tried E =Fxcos0 but only ended up with 243kJ
What distance in the diagram is ##50\cos(8°)##m?
 
Specific to this exercise, ##W=\Delta E_P## is a better fit than ##W=Fd\cos \theta##
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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