Work done by gravity on a car rolling down a hill

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The discussion centers on calculating work done by gravity on a car rolling down a hill, with a focus on the formula E = F x cos(θ). A participant mentions obtaining 243 kJ but questions the values used for force (F), distance (x), and angle (θ). The conversation suggests that using the work-energy principle, W = ΔE_P, is more appropriate for this scenario than the traditional formula. Additionally, there is a query about the specific distance represented by 50 cos(8°) m in the context of the problem. The thread emphasizes the importance of correctly applying the relevant formulas to accurately determine the work done by gravity.
physicsmaster123
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I tried E =Fxcos0 but only ended up with 243kJ
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What values of ##F##, ##x##, and ##\theta## did you use and why?
 
Hint: What is the textbook definition of ##\theta## in the formula you stated?
 
Last edited:
physicsmaster123 said:
I tried E =Fxcos0 but only ended up with 243kJ
What distance in the diagram is ##50\cos(8°)##m?
 
Specific to this exercise, ##W=\Delta E_P## is a better fit than ##W=Fd\cos \theta##
 
If have close pipe system with water inside pressurized at P1= 200 000Pa absolute, density 1000kg/m3, wider pipe diameter=2cm, contraction pipe diameter=1.49cm, that is contraction area ratio A1/A2=1.8 a) If water is stationary(pump OFF) and if I drill a hole anywhere at pipe, water will leak out, because pressure(200kPa) inside is higher than atmospheric pressure (101 325Pa). b)If I turn on pump and water start flowing with with v1=10m/s in A1 wider section, from Bernoulli equation I...

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