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Work done is the area under a voltage against charge graph

  1. Nov 24, 2013 #1
    1. The problem statement, all variables and given/known data

    question_zpsa4cb5b1b.jpg

    2. Relevant equations

    Area of a triangle is 0.5 × b × h
    ΔW=VΔQ

    3. The attempt at a solution

    I drew a straight line graph from the origin with end point 4.5V 9.0 microF
    energy is a work done = .5QV


    There is a mark in the mark scheme for ΔW=VΔQ explained.

    What do you think I need to say for this mark?

    any help gratefully received
     
  2. jcsd
  3. Nov 24, 2013 #2

    Redbelly98

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    Staff Emeritus
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    Homework Helper

    Your physics textbook, and perhaps your class lecture notes, should have an explanation of electric potential and how it relates to charge as well as work or energy. I would take a look at that.
     
  4. Nov 24, 2013 #3
    Hi Redbelly thanks for responding.
    I have just read in my notes that the energy stored in the capacitor is equal to the work done to force the extra charge onto the plates.

    So ΔE=VΔQ
    So V is changing and I guess if we make the increments very small in Q then the areas of each strip under the line add up to the total area under the triangle with base Q and Height V.
    Thanks again
     
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