- #1
san203
Gold Member
- 41
- 1
A trivial question.
I know that current is the amount of charge passing per unit time across a area.
And Potential difference is change in potential or change in potential energy per unit charge or work done per unit charge.
And also from Ohms law, V is directly proportional to I. So increasing potential difference or voltage should increase current. But how does increasing work done on a charge carrier increase the no. of such charge carriers passing through a given area?
Secondly, any kind of potential actually changes with position,right? So as a electron moves from higher to lower potential, it experiences a potential drop. But why does the potential drop increase across a resistor? After browsing related threads, the answers state things like loss of energy as heat and alike. I agree that the kinetic energy of charge carriers continuously changes due to collision which in turn change into Thermal energy and heat up the resistor, but what relation does this have with a more significant potential drop?(or am i just assuming things here)?
I am hoping to get answers from the Work point of view.
I know that current is the amount of charge passing per unit time across a area.
And Potential difference is change in potential or change in potential energy per unit charge or work done per unit charge.
And also from Ohms law, V is directly proportional to I. So increasing potential difference or voltage should increase current. But how does increasing work done on a charge carrier increase the no. of such charge carriers passing through a given area?
Secondly, any kind of potential actually changes with position,right? So as a electron moves from higher to lower potential, it experiences a potential drop. But why does the potential drop increase across a resistor? After browsing related threads, the answers state things like loss of energy as heat and alike. I agree that the kinetic energy of charge carriers continuously changes due to collision which in turn change into Thermal energy and heat up the resistor, but what relation does this have with a more significant potential drop?(or am i just assuming things here)?
I am hoping to get answers from the Work point of view.