Work-Kinetic Energy Contrasting Newton's Laws?

AI Thread Summary
The discussion revolves around applying the work-kinetic energy theorem and Newton's laws to a problem involving a bullet's acceleration in a rifle barrel. The initial calculations for kinetic energy (KE) and net force were incorrect due to a failure to square the velocity, leading to confusion in the results. After correcting the calculations, the final KE was found to be significantly higher, illustrating the bullet's immense acceleration. The average net force was recalculated, confirming the relationship between work, energy, and force in this context. The conversation highlights the importance of accuracy in applying physics equations to avoid errors in understanding motion.
latitude
Messages
54
Reaction score
0

Homework Statement




This is a question that's supposed to prove to us that you can use the work-kinetic energy theorem as a second theory of motion. Except I keep getting different answers when I work it out first w/ KET and second with Newton's Laws. So I'm definitely NOT fulfilling the objective here...

In a rifle barrel, a 15 g bullet is accelerated from rest to a speed of 780 m/s.
a) Find KE, at rest AND when it reaches 780 m/s.
b) Find work done.
c) Barrel = 72 cm long. Find mag. of average net force with Fnet = W/delta'r'cos(theta), where delta'r'cos(theta) is the displacement.
And then you find acceleration w/ Newton's Laws and the net force.

Homework Equations


KE = 1/2mv^2, W = kf - ki, Fnet = ma


The Attempt at a Solution


At initial position, KE = 0
At final speed, KE = 5.85 J

Net force = 5.85 / (0.72m)(1) = 8.125 N (??)

Constant acceleration. This is so wrong... 422500 m/s^2
Using vf^2 = vi^2 + 2a(x)

So my Fnet here = (0.015kg)(422500 m/s^2)...

Thanks!
 
Physics news on Phys.org
your KE final is wrong. it should be much bigger than that.
 
Last edited:
D'oh! I totally forgot to square the velocity. Um. Yeah. Now everything works. Thanks...
Bullets have a friggin' huge acceleration! Zowee! Wouldn't want to get hit by one of those!
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top