Work performed on a proton between two charged plates

AI Thread Summary
To calculate the work performed on a proton moving between two charged plates separated by 0.05 m and a potential difference of 20 V, the relevant formula is W = qV*cosθ. The charge of the proton is 1.6 x 10^-19 C, and since the proton moves towards the positively charged plate, the angle θ is 180 degrees, indicating that the work done is negative. The force on the proton is determined by the electric field, which is derived from the potential difference and the distance between the plates. Ultimately, the work done can be calculated using the values provided, confirming that it is indeed negative work due to the direction of movement relative to the electric field.
KidDreamer
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Homework Statement


A set of parallel conducting plates are separated by .05 m. When the plates are fully charged to a potential difference of 20 V, how much work would have to be performed to move a proton from the negatively charged plate to the positively charged plate?

My second question would be, is it negative work because its moving a positive charge towards the postive plate?


Homework Equations


V = k*q/r
We = qV
V = Ed



The Attempt at a Solution


20 * ? I am sorry i just don't understand this concept that well
 
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Work = F*d*cosθ.
Here force on the proton is E*q away from the positive plate.
Proton is moving towards the +ve plate. So θ = 180 degrees.
With these information find W.
 
Wait...so I understand it being 180 degrees...but i do i need to use the protons charge as 1.6*10^-16 to find the force applied first?
 
KidDreamer said:
Wait...so I understand it being 180 degrees...but i do i need to use the protons charge as 1.6*10^-16 to find the force applied first?
Yes.
The final formula will be
W = V*q*cosθ.
 

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