# Work question

1. Nov 20, 2013

### hey123a

1. The problem statement, all variables and given/known data

A cable lifts a 1200
kg elevator at a constant velocity for
a distance of 35 m. What is the work done by
(a)
the tension in the cable and
(b)
the elevator's weight?

2. Relevant equations

W = fscos(theta)

3. The attempt at a solution

okay i already know the answer to the solution and how to do it, however, when i first interpreted the question i thought the answer was zero because it says that it moves at a constant velocity. if its at a constant velocity then acceleration is zero. since f = ma, and acceleration is zero then force is equal to zero, so that means work is also equal to zero since W=fscos(theta)
however the answer to the question is actually

Solution: (a) 4.1 x 10 5J, (b) -4.1 x 10 5J

again, i know how to get the right answer but i would like to know what was wrong with my initial thinking

2. Nov 20, 2013

### Tanya Sharma

The net force is zero.Hence net work done is zero.But the work done by the tension in the cable and the weight are non zero.

You can easily deduce this from the answers you have got.The magnitude of the work done by the two forces are equal,but that of the tension is positive while that of the weight is negative.