Working with phasors (Circuits, such as complex power)

AI Thread Summary
To convert a phasor from polar form to rectangular form, use the cosine and sine functions to extract the real and imaginary components, respectively. For a phasor represented as 18.265 at an angle of 39.9 degrees, the conversion involves calculating the real part as 18.265 * cos(39.9) and the imaginary part as 18.265 * sin(39.9), resulting in approximately 14.02 + j11.71. The exponential component of phasors is often implied, allowing for shorthand notation without explicitly including the rotating motion. This method is essential for working with complex power in electrical circuits. Understanding these conversions is crucial for analyzing circuit behavior effectively.
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Homework Statement


I am going over examples in my textbook and I came across this:
upload_2017-4-17_14-24-15.png

I don't understand how they converted 18.265 at angle of 39.9 to 14.02+j11.71

Homework Equations


I know how to convert from the imaginary numbers into the angle form, usually I use:
upload_2017-4-17_14-25-47.png

Is there another equation when going in the other direction, or do I use the same ones. I will have two equations and two unknowns, one with tan and one with the square root? It seems a bit complicated and I feel like I am missing out on something, but I can't find it on my formula sheet or in my notes so I am a bit confused. Thanks !
 
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It's akin to converting a vector in polar form to rectangular form. Use cos and sin to extract the real and imaginary component magnitudes.
 
gneill said:
It's akin to converting a vector in polar form to rectangular form. Use cos and sin to extract the real and imaginary component magnitudes.
I will use something like this
upload_2017-4-17_14-45-4.png

even if I don't have an exponential ?
 
gneill said:
It's akin to converting a vector in polar form to rectangular form. Use cos and sin to extract the real and imaginary component magnitudes.
Ok, Ok. I take the cos of the angle and multiply by the coefficient that becomes the real part, and then I take sin and multiply which is the imaginary part?
 
Cocoleia said:
I will use something like this
View attachment 195299
even if I don't have an exponential ?
Yes. For phasors the exponential is implied, and we use the magnitude and phase angle for its shorthand notation.

The full form of the phasor is ##P = A e^{j(ω t + Φ)}##. The "ωt" part represents the rotating motion of the phasor. Splitting it: ##P = A e^{jωt} e^{j Φ}##. When the angular frequency ω is the same for all phasors in a system we just drop the rotating component from the notation and take it as implied. That leaves ##A e^{j Φ}## as the unique part of the phasor, and that can be represented by a complex number (rectangular form) or magnitude and angle (polar form) in phasor "shorthand".
Cocoleia said:
Ok, Ok. I take the cos of the angle and multiply by the coefficient that becomes the real part, and then I take sin and multiply which is the imaginary part?
Yes.
 
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