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(y - a)^2 = p(x - e)

  1. Jan 1, 2010 #1
    I'm looking at an example of a problem in my book and one line says

    (y - a)^2 = p(x - e)

    and then it says by subtracting they get

    2ay - a^2 = pe

    I'm not seeing what they subtracted to get that...

    Please help me!!

  2. jcsd
  3. Jan 1, 2010 #2
    Re: Confusion

    Nevermind, I figured it out...I was actually subtracting out an equation from earlier in the problem.
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