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ConquestAce
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Homework Statement
A tree loses water to the air by the process of transpiration at the rate of 110 g/h. This water is replaced by the upward flow of sap through vessels in the trunk.
If the trunk contains 1900 vessels, each 100 μm in diameter, what is the upward speed of the sap in each vessel? The density of tree sap is 1040 kg/m3.
Known :
110g/hr water loss
d = 100μm
D = 1040kg/m^3
Homework Equations
berulinni's equation and contintuty equation :
p + 0.5*rho*v^2+rho*g*y = c
(v_1)(A_1) = (v_2)(A_2)
The Attempt at a Solution
Initially I converted the water loss to kg/s which was (110g/hr)*(1hr/3600seconds) and since 1 kg of water = 1L of water the water loss to be replaced by sap rate was 3.055*10^-5 m^3/s
Then calculated the volume of the sap to be 3.054x10-8 m^3 using Vsap=Vwater
Divided by vessels to get 1.60737*10^-11 m^3
And from now on, I only have uncertainties:
and a lot of possibilies but not sure how I can proceed.