Yes, that is the amount of the loan Clarissa can afford to borrow.

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Problem:

Clarissa wants to buy a new car. Her loan officer tells her that her annual rate is 8%, compuded continously, over a four-year term. Clarissa informs her loan officer that she can make qual monthly payments of $225. How much can Clarissa afford to borrow?

I figured that she will pay $10800 (48 months * $225)

Skipping the differential derivation...

If A(t)=Ke^.08t ...whre t=4 and A(4)=10800...then k=$7842.41...is this the amount (principle) of the loan? I'm not accounting friendly :(
 
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that is correct
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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