Zero voltage, non-zero current?

AI Thread Summary
When a solar panel is short-circuited, it generates current without voltage, resulting in no external power delivery due to the lack of an external load. The current measured by an ammeter is influenced by the internal resistance of the device, which allows for a negligible voltage to be present, enabling current measurement. In the case of a capacitor, while it can draw significant current initially, it does not dissipate power as it only stores energy. The internal resistance of all devices means that power can be dissipated internally when short-circuited, which can lead to destructive outcomes. Therefore, while current exists in these scenarios, the effective power output remains minimal unless an appropriate load is applied.
Artlav
Messages
161
Reaction score
1
Reading about solar panels i came across a peculiar description - "When the panel is short circuited, there is current but no voltage, so no power is being generated."

How does that work?
What does the current represent in that case, and what moves the needle of an ammeter?


Another instance of the same problem happens when charging a big capacitor.
At first, there is essentially no voltage across it, but several dozens of amperes of current is going into it. Once again power, 0*I, is about zero, and yet the power is being consumed into the capacitor.

What am i missing here?
 
Physics news on Phys.org
When the solar cell is shorted, there is no external load and so no place external to the cell for there to be an IR drop. Hence, no power is externally delivered. Now in the case of an ammeter, an ideal ammeter is a device that draws no voltage (i.e. suffers no IR drop) but yet (somehow) measures current. In practice, a real ammeter draws "negligible" voltage and uses that negligible voltage to sense current. And so, a solar cell actually delivers power, albeit "negligible", to a real ammeter.

Thank about your capacitor question again. From a circuits perspective, no current flows "through" an ideal capacitor; it merely stores energy but can never dissipate power. Furthermore, it is the current that may changed instantaneously, but not the voltage.
 
Reading about solar panels i came across a peculiar description - "When the panel is short circuited, there is current but no voltage, so no power is being generated."

There is a voltage and there is current and power dissipated. Just not much of it is being generated external to the device. None if you have a perfect conductor.


All devices no matter how good have internal resistance(and inductance and capacitance)

So when you place a short circuit across the output of your solar panels (or capacitors or battery etc) the voltage is developed across the internal components and the power is dissipated there.

Of course this is why placing a short circuit across any power source can be quite destructive. The internal resistance is usually designed to be as low as possible. A lot of power could be dissipated, resulting in sometimes violent reactions.

What does the current represent in that case, and what moves the needle of an ammeter?

An ammeter does not represent a short circuit. It has an internal calibrated resistance. often in the form of a thick piece of copper.

Placing an ammeter across the pv panels or capacitor does provide a load and power is dissipated within the ammeter. Just not very much. In the case of a moving needle ammeter very little power is required to move the needle full scale, so the load is very small. In a digital ammeter the load is even smaller as they are much more sensitive.
 
Thread 'Griffith, Electrodynamics, 4th Edition, Example 4.8. (Second part)'
I am reading the Griffith, Electrodynamics book, 4th edition, Example 4.8. I want to understand some issues more correctly. It's a little bit difficult to understand now. > Example 4.8. Suppose the entire region below the plane ##z=0## in Fig. 4.28 is filled with uniform linear dielectric material of susceptibility ##\chi_e##. Calculate the force on a point charge ##q## situated a distance ##d## above the origin. In the page 196, in the first paragraph, the author argues as follows ...
Thread 'Inducing EMF Through a Coil: Understanding Flux'
Thank you for reading my post. I can understand why a change in magnetic flux through a conducting surface would induce an emf, but how does this work when inducing an emf through a coil? How does the flux through the empty space between the wires have an effect on the electrons in the wire itself? In the image below is a coil with a magnetic field going through the space between the wires but not necessarily through the wires themselves. Thank you.
Back
Top