# Zeros of a polynomial

• ehrenfest
In summary, the problem is to find the zeros of the polynomial P(x) = x^4-6x^3+18x^2-30x+25, knowing that the sum of two of them is 4. Using Viete's formulas, it can be shown that x_1 + x_2 = 4 and x_3 + x_4 = 2. Substituting these values into the Viete relations, it can be simplified to two equations in x_1x_2 and x_3x_4. Solving these equations will give the values of x_1x_2 and x_3x_4, which can then be used to find the zeros of the polynomial

#### ehrenfest

[SOLVED] zeros of a polynomial

## Homework Statement

Find the zeros of the polynomial

$$P(x) = x^4-6x^3+18x^2-30x+25$$

knowing that the sum of two of them is 4.

## Homework Equations

http://en.wikipedia.org/wiki/Viète's_formulas

## The Attempt at a Solution

Let x_1,x_2,x_3,x_4 be the complex roots and let x_1 +x_2 = 4. Here are the Viete relations in this case:

$$x_1+x_2+x_3+x_4 = 6$$

$$x_1 x_2 +x_1 x_3 +x_1 x_4 + x_2 x_3 + x_2 x_4 +x_3 x_4 = 18$$

$$x_1 x_2 x_3 + x_1 x_3 x_4 +x_2 x_3 x_4 +x_1 x_2 x_4= 30$$

$$x_1 x_2 x_3 x_4 = 25$$

The first one implies that x_3 +x_4 =2. And then the second one implies that x_1 x_2 + x_3 x_4 = 10 but that is as far as I can get.

ehrenfest said:
x_1 +x_2 = 4 … x_3 +x_4 =2.

Hint: so x_2 = 4 - x_1 and x_4 = 2 - x_3.

Go substitute!

Do you mean into

$$P(x) = x^4-6x^3+18x^2-30x+25$$

?

No … I mean substitute into your Viete relations.

Sorry tiny-tim, I don't know see why that helps:

For the second Viete relation I get:

$$4x_1 - 2 x_3 - x_1^2-x_3 ^2+ x_1 x_3 = 10$$

For the third one I get

$$8x_1 + 8x_3 - 2 x_1 ^2 - 4 x_3^2 = 30$$

For the fourth one I get

$$8 x_1 x_3 + x_1 ^2 x_ 3^2 - 2x_1 ^2 x_3 - 4 x_1 x_3 ^2 = 25$$

Is there a simple way to solve these equations?

hmm … turned out more complicated than I thought.

Well … that's what happens in exams sometimes … you try something, and it doesn't work, so you try the next most obvious thing …

Now this will work:

in your
ehrenfest said:
$$x_1 x_2 +x_1 x_3 +x_1 x_4 + x_2 x_3 + x_2 x_4 +x_3 x_4 = 18$$

$$x_1 x_2 x_3 + x_1 x_3 x_4 +x_2 x_3 x_4 +x_1 x_2 x_4= 30$$

put (x_1 + x_2)s together, and (x_3 + x_4)s, and you should get two equations in x_1x_2 and x_3x_4, from which you get x_1x_2 = … and x_3x_4 = … ?