- #1
jt316
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I need help figuring out the solution to this diff.eq.
y(x) = x + (1/2)*∫(from u=-1 to 1)[ ( 1-| x – u | ) y(u) du] , x є [ -1, 1]
I have to show that:
y``(x) + y(x) = 0 , x є [ -1, 1]
subject to:
y(1) + y(-1) = 0
y`(1) + y`(-1) = 2
Thanks for any help you can give.
y(x) = x + (1/2)*∫(from u=-1 to 1)[ ( 1-| x – u | ) y(u) du] , x є [ -1, 1]
I have to show that:
y``(x) + y(x) = 0 , x є [ -1, 1]
subject to:
y(1) + y(-1) = 0
y`(1) + y`(-1) = 2
Thanks for any help you can give.
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