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How I can use a vertical bar to represent evaluation in LaTeX 
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#1
Apr1608, 06:58 PM

P: 743

Hey guys. This might not be the right place for this, but any ideas on how I can use a vertical bar to represent evaluation in LaTeX?
Example [tex] \displaystyle \frac{d}{dt} _{t=0} f(t) [/tex] I would like the vertical bar to be the size of the differential. I've tried using \left, \right, \vert, etc. but nothing seems to work. Thanks a lot in advance. 


#2
Apr1608, 08:50 PM

HW Helper
P: 2,249

Hi Kreizhn,
Is this it? [tex]\left. \frac{d}{dt} \right_{t=0} f(t)[/tex] which is given by \left. \frac{d}{dt} \right_{t=0} f(t) Using either \left or \right on a period means the automatic delimiter sizing takes place, but only one delimiter is shown. 


#3
Apr1608, 08:56 PM

P: 743

Excellent, thank you



#4
Apr1608, 11:32 PM

Sci Advisor
HW Helper
PF Gold
P: 4,139

How I can use a vertical bar to represent evaluation in LaTeX
\frac{d}{dt} \bigg_{t=0} f(t) achieves a similar effect
with manual sizing (by using two g's) and the unneeded \left. tag. [tex]\frac{d}{dt} \bigg_{t=0} f(t)[/tex] 


#5
May511, 12:35 PM

P: 17

I'm using lyx and I'm having difficulty trying to find the code for this vertical line. Any suggestions? I use the  but it's extremely small.



#6
May511, 12:42 PM

P: 743

Maybe try \?
The height of the vertical line will be determined by the {stuff} in between the \left. {stuff} \right. If it's not naturally big, you may want to add an "invisible tower." My invisible tower is called \xstrut, and is defined as follows \newlength{\myVSpace}% the height of the box \setlength{\myVSpace}{3ex}% the default, \newcommand\xstrut{\raisebox{.5\myVSpace}% symmetric behaviour, {\rule{0pt}{\myVSpace}}% } To change the height of the box, change \setlength{\myVSpace}{Your number here} 


#7
Feb1912, 12:15 AM

P: 23

\mathbf{M \bigg_{x^k} \Delta x^k = f(x^k)}
[tex] \mathbf{M \bigg_{x^k} \Delta x^k = f(x^k)}[/tex] 


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