- #1
schattenjaeger
- 178
- 0
find the minimum distance between the origin and the surface z^2=[8-y^2-x^4*y^2]/2
so d=sqrt(x^2+y^2+z^2)^(1/2) where for z^2 I sub in that expression in x and y?
so then I take the partials of d wrt to x and y and set those equal to 0, then I solved that system of equations and got x=+-1 and y=+-1 but I'm not sure about that. I also got x=0 and y=0 but I guess that's the max distance since it's the initial point? I dunno. I got the ultimate distance being sqrt(5) by plugging 1 back into the expression for d, you're welcome to practice on it too but I just need to know if the procedure was right
so d=sqrt(x^2+y^2+z^2)^(1/2) where for z^2 I sub in that expression in x and y?
so then I take the partials of d wrt to x and y and set those equal to 0, then I solved that system of equations and got x=+-1 and y=+-1 but I'm not sure about that. I also got x=0 and y=0 but I guess that's the max distance since it's the initial point? I dunno. I got the ultimate distance being sqrt(5) by plugging 1 back into the expression for d, you're welcome to practice on it too but I just need to know if the procedure was right