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Canaldigger
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Homework Statement
I(a)= 11A, I(b)= 2.5A, I(c)= 3A. Apply KCL at node X to find I(x).
This question seems really simple as it tells me what to do and where to do it, but am I missing something or not remembering to apply some concept?
The Attempt at a Solution
My attempt: I assigned current flowing towards node x as positive and away as negative.
Ʃi=0; I(a)+I(b)-I(c)-I(x) = 0
After plugging in, I(x) = 10.5A
Is that all there is to the question?
I don't think this answer is correct and rather I should redraw the circuit as a three loop one and use Current divider equations.
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