- #1
kasse
- 384
- 1
Homework Statement
What is the steady state solution to the equation
4y''+4y'+17y=202cos3t (*) ?
2. The attempt at a solution
The steady state solution is, if I've got it right, only the particular solution. It's got to be on the form
Kcos3x+Msin3x.
I calculate the derivatives, put into (*) and find it to be 122,19 cos 3t + 210 sin 3t.
It's normal to write steady state solutions on the form
Ccos(ωt-η).
How can I do that?