- #1
kasse
- 384
- 1
If
f(x,y) = 4xy, for 0<x<1, 0<y<1
f(x,y) = 0, elsewhere
What's the probability that X<Y?
It seems likely that the probability is 0.5, but how can I show it matematically?
f(x,y) = 4xy, for 0<x<1, 0<y<1
f(x,y) = 0, elsewhere
What's the probability that X<Y?
It seems likely that the probability is 0.5, but how can I show it matematically?