- #1
Timma300
- 2
- 0
Hello, I am building a scissor lift for a design project. I located a formula for calculating the amount of force required to lift a weight as given:
F=(W+(Wa/2))/(tan(theta))
Where F is the amount of force required, W is the weight of the payload and the load platform, Wa is the weight of the scissor arms, and theta is the angle that the scissor makes with the horizontal. I found the equation here, on this webpage: http://www.engineersedge.com/mechanics_machines/scissor-lift.htm. I understand that the higher the scissor lift is raised, the less force that is required to raise it. My question is about a multi-scissor lift. The site describes the equation for a multi-scissor lift as the exact same equation, except you multiply F by the number of stacked scissor mechanisms. Does this mean that a double scissor lift will require half as much force or twice as much force to raise?
F=(W+(Wa/2))/(tan(theta))
Where F is the amount of force required, W is the weight of the payload and the load platform, Wa is the weight of the scissor arms, and theta is the angle that the scissor makes with the horizontal. I found the equation here, on this webpage: http://www.engineersedge.com/mechanics_machines/scissor-lift.htm. I understand that the higher the scissor lift is raised, the less force that is required to raise it. My question is about a multi-scissor lift. The site describes the equation for a multi-scissor lift as the exact same equation, except you multiply F by the number of stacked scissor mechanisms. Does this mean that a double scissor lift will require half as much force or twice as much force to raise?