# Solve the trig

by hayowazzup
Tags: solve, trig
 P: 64 1. The problem statement, all variables and given/known data 1 = 121 sinθ *cosθ + 592.9 (cos²θ) 2. Relevant equations 3. The attempt at a solution 1= 60.5 * 2 *sin θ *cosθ + 592.9 (cos²θ) 1= 60.5 sin 2θ + 592.9 (cos²θ) 1-60.5 sin 2θ / cos θ cos θ= 592.9 am i doing it rite? i don't know what to do
 P: 664 Use $$sin^2 + cos^2 =1$$
 P: 64 but i don't know how to get rid of sin θ *cosθ
P: 550

## Solve the trig

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 Sci Advisor HW Helper Thanks P: 25,158 You wrote sin(theta)*cos(theta) in terms of sin(2*theta). Write cos(theta)^2 in terms of cos(2*theta).

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