
#1
Jun608, 03:20 AM

P: 64

1. The problem statement, all variables and given/known data
1 = 121 sinθ *cosθ + 592.9 (cosēθ) 2. Relevant equations 3. The attempt at a solution 1= 60.5 * 2 *sin θ *cosθ + 592.9 (cosēθ) 1= 60.5 sin 2θ + 592.9 (cosēθ) 160.5 sin 2θ / cos θ cos θ= 592.9 am i doing it rite? i don't know what to do 



#2
Jun608, 03:22 AM

P: 664

Use [tex] sin^2 + cos^2 =1 [/tex]




#3
Jun608, 04:01 AM

P: 64

but i don't know how to get rid of sin θ *cosθ




#4
Jun608, 07:32 AM

P: 550

Solve the trig
....




#5
Jun608, 08:20 AM

Sci Advisor
HW Helper
Thanks
P: 25,158

You wrote sin(theta)*cos(theta) in terms of sin(2*theta). Write cos(theta)^2 in terms of cos(2*theta).



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